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3 years ago

How do you know that 4/11 is a reapeating decimal

Mathematics

2 answers:

Evgen [1.6K]3 years ago

8 0

Answer:

Because 4 divided by 11 does not have an exact answer, it just keeps going on.

Step-by-step explanation:

NARA [144]3 years ago

3 0

Answer:

4/11 is a repeating decimal because 4÷11= 0.36 repeating

Step-by-step explanation:

You might be interested in

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago

Suppose a population of 250 crickets doubles in size every 3 months. How many crickets will there be after 2 years?

aivan3 [116]

The equation is:
f ( t )=

6 0

3 years ago

Read 2 more answers

Look at the pictures pleaseeeeee

Alex

Answer:

Step-by-step explanation:

There is missing information in the task: HD║FG !!!!!

∠HDE ≅ ∠FGE and ∠EHD ≅ ∠EFG

ΔEHG ~ ΔEFG (AAA theorem of similarity)

m∠F = 22°

m∠G = 89°

3 0

3 years ago

naomi needs 2 cups of chopped apples for a fruit salad she is making .she only has a 1/4 cup. how many times will naomi need to

Lilit [14]

1/4 × 8 times = 2 cups
ANSWER : 8 times

5 0

3 years ago

Read 2 more answers

3-4 litros de jugo de frutilla 1 y 1-2 litros de jugo de manzana 1-8 litro de jugo consentrado de limón . 1 y 1-2 litro de agua.

Neko [114]

Answer:

Hay 3,875 litros de jugo multifrutal.

Step-by-step explanation:

(Se asume que el problema fue propuesto en un país distinto a los Estados Unidos, razón por la cual se emplea las reglas del Sistema Internacional.)

La capacidad de jugo multifrutal en el bidón se obtiene con la mezcla de cada jugo frutal y se logra mediante la suma de cada capacidad. A partir del enunciado, tenemos que la capacidad del jugo multifrutal es:

$V = \frac{3}{4}\,L + 1\,\frac{1}{2}\,L + \frac{1}{8}\,L + 1\,\frac{1}{2}\,L$

$V = \frac{3}{4}\,L + 1\,L + \frac{1}{2}\,L + \frac{1}{8}\,L + 1\,L + \frac{1}{2}\,L$

$V = 3,875\,L$

Hay 3,875 litros de jugo multifrutal.

5 0

3 years ago