1/-x*5y/-8
-1/x × (-5y/8)
5y/8x
Answer:
Third option.
Step-by-step explanation:
You need to cube both sides of the equation. Remember the Power of a power property:

![\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d})\\\\(\sqrt[3]{162x^cy^5})^3=(3x^2y(\sqrt[3]{6y^d}))^3\\\\162x^cy^5=27x^6y^36y^d](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%3D3x%5E2y%28%5Csqrt%5B3%5D%7B6y%5Ed%7D%29%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%29%5E3%3D%283x%5E2y%28%5Csqrt%5B3%5D%7B6y%5Ed%7D%29%29%5E3%5C%5C%5C%5C162x%5Ecy%5E5%3D27x%5E6y%5E36y%5Ed)
According to the Product of powers property:

Then. simplifying you get:

Now you need to compare the exponents. You can observe that the exponent of "x" on the right side is 6, then the exponent of "x" on the left side must be 6. Therefore:

You can notice that the exponent of "y" on the left side is 5, then the exponent of "x" on the left side must be 5 too. Therefore "d" is:

Answer:
x = 3
Step-by-step explanation:
The smaller triangle and larger one are similar, so corresponding sides are proportional.
8/4 = (8 +(x -1))/5
10 = x +7 . . . . . . . . . multiply by 5 and simplify
3 = x . . . . . . . . . subtract 7
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<em>Alternate solution</em>
The short segments are also proportional:
(x -1)/(5 -4) = 8/4
x -1 = 2 . . . . simplify
x = 3 . . . . . . add 1
(x+3)(2x-6)=26
2x(to the second power)-18=26
2x(to the second power) -18-26=26-26
2x(to the second power)-44 = 0
x=square root of 22,x= negative square root of 22
decimal form : x = 4.69042,x= -4.69042
Is the question asking what is the product(end value) of 2x3 +3.4y when x=3 and y=4?