To simplify the expression, we distribute terms accordingly. It is done as follows:
<span>(3a – 4b)(a + b)
3a</span>² + 3ab -4ab -4b²
3a² - ab -4b²
Therefore, the correct answer is option A, <span>3a^2– ab – 4b^2.
Hope this answers the question. Have a nice day. Please feel free to ask more questions.</span>
Answer:
Step-by-step explanation:
Hello!
Given the variables
Y: standardized history test score in third grade.
X₁: final percentage in history class.
X₂: number of absences per student.
<em>Determine the following multiple regression values.</em>
I've estimated the multiple regression equation using statistics software:
^Y= a + b₁X₁ + b₂X₂
a= 118.68
b₁= 3.61
b₂= -3.61
^Y= 118.68 + 3.61X₁ - 3.61X₂
ANOVA Regression model:
Sum of Square:
SS regression: 25653.86
SS Total: 36819.23
F-ratio: 11.49
p-value: 0.0026
Se²= MMError= 1116.54
Hypothesis for the number of absences:
H₀: β₂=0
H₁: β₂≠0
Assuming α:0.05
p-value: 0.4645
The p-value is greater than the significance level, the decision is to not reject the null hypothesis. Then at 5% significance level, there is no evidence to reject the null hypothesis. You can conclude that there is no modification of the test score every time the number of absences increases one unit.
I hope this helps!
Answer:
x = 0 1 -1 -2
y = -3 -4 -2 -1
Step-by-step explanation:
equation : 3y+9x = -9
when x = 1
3y+3x = -9
or, 3y + 3×1= -9
or, 3y+3=-9
or, 3y = -12
so, y = -4
Again
Let's suppose x as -1
3y+3x= -9
or, 3y+ 3×-1 = -9
or, 3y-3 = -9
or, 3y = -6
y = -2
Let's suppose x as -2 now,
3y+3x = -9
3y+3×-2 = -9
or, 3y-6 = -9
or, 3y = -3
so, y = -1
Answer:
D
Step-by-step explanation:
A function is a set of points which never repeat x values. The only answer that follows that rule of a function is the last one, d.
Hope this helps! :D
Answer:
0.04,0.25.0.52
Step-by-step explanation:
Given that you throw a dart at a circular target of radius 10 inches.
Assuming that you hit the target and that the coordinates of the outcomes are chosen at random,
probability that the dart falls
(a) within 2 inches of the center
Here favourable region has area of a circle with radius 2 inches and sample space has area of 10 inches
Prob = 
(b) within 2 inches of the rim.
For within two inches from the rim we have to select area of the ring i.e. area of big circle with 10 inches - area of smaller circle with 10-2 inches
Prob= 
c) within I quadrant
area of I quadrant / area of circle=0.25
d) within I quadrant and within 2 inches of the rim
= I quadrant area + 2 inches ring area - common area
= 
