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2 years ago

Please help!<3 tysm if u helped

Mathematics

1 answer:

Vilka [71]2 years ago

5 0

Answer:

x = 0 1 -1 -2

y = -3 -4 -2 -1

Step-by-step explanation:

equation : 3y+9x = -9

when x = 1

3y+3x = -9

or, 3y + 3×1= -9

or, 3y+3=-9

or, 3y = -12

so, y = -4

Again

Let's suppose x as -1

3y+3x= -9

or, 3y+ 3×-1 = -9

or, 3y-3 = -9

or, 3y = -6

y = -2

Let's suppose x as -2 now,

3y+3x = -9

3y+3×-2 = -9

or, 3y-6 = -9

or, 3y = -3

so, y = -1

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3x²-9x+1+0 Find the discriminant

Sindrei [870]

Answer:

$\boxed{D = 69}$

Step-by-step explanation:

The given quadratic equation is:

$3x^2-9x+1 = 0$

Comparing it with the standard form of Quadratic Equation $ax^2+bx+c = 0$ , we get:

a = 3, b = -9 and c = 1

Discriminant = b² - 4ac

D = (-9)²-4(3)(1)

D = 81 - 12

D = 69

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3 years ago

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hodyreva [135]

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3 years ago

Need all these tomorrow!!!!! thank you all soooooOOOOOOooOoOOooOOoO much!!!!!

nordsb [41]

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3 years ago

The perimeter of a particular square and the circumference of a particular circle are equal. What is the ratio of the area of th

oksano4ka [1.4K]

<h2>Ratio of area of the square to the area of the circle = π/4</h2>

Step-by-step explanation:

Let the side of square be a and radius of circle be r.

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Given that

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$a=\frac{\pi r}{2}$

We need to find the ratio of the area of the square to the area of the circle.

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Area of the circle = πr²

$\texttt{Ratio of area of the square to the area of the circle =}\frac{a^2}{\pi r^2}\\\\\texttt{Ratio of area of the square to the area of the circle =}\frac{\left ( \frac{\pi r}{2}\right )^2}{\pi r^2}\\\\\texttt{Ratio of area of the square to the area of the circle = }\frac{\pi}{4}$

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3 years ago

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lana66690 [7]

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