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Romashka-Z-Leto [24]
3 years ago
5

If EF = x + 5, DC = 2x + 4, and AB = 2x + 2. Find EF.​

Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

B *second one down.

Step-by-step explanation:

EF = 1/2(AB + CD)

x+5 = 1/2 (2x + 2 + 2x+4)   Combine the like terms on the right.

x+5 = 1/2 (4x + 6)                Remove the brackets.

x+5 = 1/2*4x + 1/2*6

x+5 = 2x + 3                       Subtract x from both sides

5 = 2x-x + 3

5 = x + 3                            Subtract 3 from both sides

5-3 = x

x = 2

EF = x + 5

EF = 2 + 5

EF = 7

The answer is B

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Area of the rectangle: 112

Step-by-step explanation:

Picture is missing: find it in attachment.

The area of a triangle is given by

A=\frac{1}{2}bh

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For triangle ABE, we know that

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So we can find the length of the base AE:

AE=b=\frac{2A}{h}=\frac{2(40)}{8}=10

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

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Learn more about area of figures:

brainly.com/question/4599754

brainly.com/question/3456442

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