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3 years ago

If EF = x + 5, DC = 2x + 4, and AB = 2x + 2. Find EF.

Mathematics

1 answer:

bonufazy [111]3 years ago

3 0

Answer:

B *second one down.

Step-by-step explanation:

EF = 1/2(AB + CD)

x+5 = 1/2 (2x + 2 + 2x+4) Combine the like terms on the right.

x+5 = 1/2 (4x + 6) Remove the brackets.

x+5 = 1/2*4x + 1/2*6

x+5 = 2x + 3 Subtract x from both sides

5 = 2x-x + 3

5 = x + 3 Subtract 3 from both sides

5-3 = x

x = 2

EF = x + 5

EF = 2 + 5

EF = 7

The answer is B

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Answer:

b. -84

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{a}{-7} - 7 = 5$

Step 2: Solve for a

Addition Property of Equality: $\displaystyle \frac{a}{-7} - 7 + 7 = 5 + 7$
[Simplify] Add: $\displaystyle \frac{a}{-7}= 12$
Multiplication Property of Equality: $\displaystyle -7 \cdot \frac{a}{-7} = 12 \cdot -7$
[Simplify] Multiply: $\displaystyle a = -84$