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3 years ago

10

Please help I will give brainliest if you are right

2 answers:

Vsevolod [243]3 years ago

4 0

Answer:

I believe its A im not exactly sure though

quester [9]3 years ago

4 0

Answer:

#2

Step-by-step explanation:

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An expression involves subtracting two numbers from a positive number. Under what circumstances with the value expression be neg

Svetach [21]

So (positive integer)-x-y can be negative
so to get a negative number as your result/answer, x+y must be greater than (positve integer) so for example

lets say (positive integer)=8
x+y must be greater than 8 to make the equation negative so
example
x=5
y=4
x+y=9
8-9=-1

7 0

3 years ago

On the first circle, what segment is a diameter? How long is it?

stiv31 [10]

Answer:

The segment that is the diameter is EB

It is 8 cm long

Step-by-step explanation:

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3 years ago

Which statement is true about this quadratic equation?<br> y=x^(2)-11x+7

Sliva [168]

Answer: <em>This quadratic equation has two real solutions.</em>

<em />

Step-by-step explanation:

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3 years ago

Example of how is the quadratic equation used in nursing?

Mumz [18]

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Step-by-step explanation:

3 0

3 years ago

I need to get the left side to equal the right side. Keeping the right side alone and not changing it.

likoan [24]

<u>To prove the trigonometric equation:</u>

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

$RHS=(\sin x+\cos x)(1-\sin x \cos x)$

We know that $\sin^2x +\cos^2x=1$ , substitute this in place of 1.

$=(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)$

Multiply each term of the first term with each term of the 2nd term.

$=\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x$

Group like terms together.

$=\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x$

$=\sin^3x +( 0)+(0) + \cos^3 x$

$=\sin^3x + \cos^3 x$

= LHS

RHS = LHS

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

Hence proved.

7 0

4 years ago