Answer:
0.03 grams
Step-by-step explanation:
Given:
An aerogel meringue weighs 1.17 grams
It is 96% air and 1.3 egg whites.
The rest is sugar.
To find:
How much sugar is in the meringue, rounded to the nearest hundredth?
Solution:
An aerogel meringue weighs = 1.17 grams
Percentage of air = 96%
Percentage of egg whites = 1.3%
Now, to find first of all to find the percentage of sugar, we will add the percentage of air with the percentage of egg whites,
96% + 1.3% = 97.3%
As here given that the remaining percentage is sugar therefore,
100% - 97.3% = 2.7%
Now, to find the quantity of sugar in meringue,
Therefore, sugar is 0.03 grams in the meringue.
Idk sorry I’m stuck in an iready lessssssooooooonnnn. Ahahahahah
You can identify that "5 over 100" can be written as a fraction. 5 will be the numerator and 100 will be the denominator:
To reduce this fraction, you need to divide the numerator and the denominator by the Greatest Common Factor (GCF) between them.
In this case, to find the GCF, you need to:
- Decompose the number into their Prime Factors:
- Notice that 5 is a common factor. Then, you need to choose the one with the lowest exponent:
Therefore, by dividing the numerator and the denominator by 5, you get:
Hence, the answer is:
Answer:
1093.96
Step-by-step explanation:
900(1+.05)⁴=1093.955625
Answer:
So you say you want some 5 digit numbers eh? Let’s consider some boundaries. 5 digit numbers range from 10,000 - 99,999. So our number is guaranteed to be between 0 and 90000.
Sometimes it’s much easier to work with concrete things. Such as the number of numbers that don’t contain any 3s. It’s really more difficult to put our finger on “at least 1” anything so we try to steer clear of it.
Anyways we’ve got 90000 numbers that have at least 1 or 0 3’s. Find one and we know the other.
So no 3’s at all right? Well you have 8 choices for the first digit (can’t choose 0 and you can’t choose 3). And then for the remaining 4 digits you have 9 choices. So that’s
8∗94=52488
Back to our initial equation, we have
90000−8∗94=37512 5 digits numbers without any 3s.
A quick (or maybe not so quick) matlab script confirms such calculations.
credits to : Trevor Squires
