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alexandr402 [8]
4 years ago
15

A train travels 226 miles from Washington, D.C.,to New York city in about 2 hours and 30 minute. What is the average speed of th

e train in miles per hour? Round to the nearest mile per hour.
Mathematics
1 answer:
nevsk [136]4 years ago
5 0
226 miles
2.5 hours

226/2.5
=90.4

90 miles/hour
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4 0
3 years ago
Based on your value of x in question #1, what is the value for ∠EHF
Ludmilka [50]

Answer:

∠EHF = 132°

Step-by-step explanation:

Both angles lie on a straight line.

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  • ∠EHF + ∠FHG = 180°
  • 2(x) + 48° = 180°
  • 2(x) = 180° - 48°
  • 2(x) = 132°
  • x = 66°

Then ∠EHF :

  • 2(x)
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2 years ago
A theater group surveyed 146 audience members after a show and found that 132 of them wanted to see the show again. Find the sta
Sophie [7]

Answer:

0.024

Step-by-step explanation:

Sample size (n) = 146 people

The proportion (p) of people who answered that they would be interested in seeing the show again is:

p=\frac{132}{146}\\ p=0.9041

The standard error for a sample of size 'n' and proportion 'p' is:

SE = \sqrt{\frac{p*(1-p)}{n}}\\SE = \sqrt{\frac{0.9041*(1-0.9041)}{146}}\\ SE=0.024

The standard error for the sample proportion of audience members who want to see the show again is 0.024.

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3 years ago
A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters
Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO  = x° (Base angle of an isosceles triangle)

∠OPR  = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x°  = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR  = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

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