X - y = 2 x + y = -3 Solve this using elimination Quickly please!!!!

Mathematics

1 answer:

blagie [28]3 years ago

7 0

The answer for x=-1
The answer for y=-5/2

I believe these are correct

You might be interested in

Cuánto es 6321 dividido 694?

Maksim231197 [3]

Answer:

9.10806916427

Step-by-step explanation:

6 0

3 years ago

Simplify 2(x - 4) + 7(x + 2).

Sauron [17]

Answer:

9x+6

Step-by-step explanation:

2(x-4)= 2x-8

7(x+2)= 7x+14

2x-8+7x+14

clt

9x6

3 0

3 years ago

Divide. −1/9÷3/4 −4/27 −1/12 1/12 4/27 PLZZZZ HELP FAST!

ivanzaharov [21]

$\frac{ - 1}{9} \div \frac{3}{4} \\ \\ \frac{ - 1}{9} \times \frac{4}{3} \\ \\ \frac{( - 1) \times 4}{9 \times 3} \\ \\ \frac{ - 4}{27}$

7 0

3 years ago

Can anyone help me. Please

faust18 [17]

Answer:

how can I help?

Step-by-step explanation:

with what?

5 0

3 years ago

Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

8 0

3 years ago