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mamaluj [8]
2 years ago
11

At a restaurant, n cups of tea are made by adding

SAT
1 answer:
Sauron [17]2 years ago
5 0

Answer:

1

Explanation:

This is just like a linear equation, since it is a positive number the units are increasing by 1 unit. If we were to plug this into a graph we can see that 2 is the y-intercept which means with 2 tea bags you have 0 cups and for every additional cup of tea you need another teabag, meaning the increase, or slope of the equation so the answer is 1.

Hope this helped :)

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Suppose that 3. 33 g of acetone at 25. 0 °c condenses on the surface of a 44. 0-g block of aluminum that is initially at 25 °c.
Vlada [557]

The final temperature on the block is 25 degrees.

Heat is a form of energy. This question shows that energy is transferred from the acetone to the metal block.

Data given;

  • M1 = 3.33g
  • T1 = 25 degrees
  • M2 = 44g
  • T2 = 25 degree
  • C1 = 124.5 J mol K
  • C2 = 0.89 J/g K
<h3>Heat Transfer</h3>

Applying the principles of heat transfer,

Heat loss = Heat gain

m1c1(T1 - T3) = m2c2(T3 - T2)\\3.33*124.5*(25.0 - T3) = 44*0.89*(T3 - 25)\\10364.625 - 414.585T3 = 39.16T3 - 979\\10364.625+979 = 414.585T3 +39.16T3\\11343.25 = 453.745T3\\T3 = \frac{11343.25}{453.745} \\T3 = 24.999\\T3 = 25

From the calculation above, the final temperature on the block is 25 degrees.

Learn more on heat transfer here;

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2 years ago
Cual es la diferencia entre estas imagenes?
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Las imagines son claro
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One fragment of a given integer n can be selected and its digits reversed (replaced with a right to left version of themselves).
andrew11 [14]

Integers are numbers without decimal points. The number could be positive, negative or zero

<h3>How to determine the maximum number from the integer</h3>

The maximum number from integer N can be determined using the following program written in Python, where comments are used to explain each line

#This prompts the user for input

num = input("Number: ")

#This iterates from 0 to 9

kount = [0 for x in range(10)]

# This iterates through the input, and updates the kount variable

for i in range(len(num)):

  kount[int(num[i])] = kount[int(num[i])] + 1

# This next two lines initialize the greatest number

greatestNum = 0

multiplier = 1

# This iterates through the kount array

for i in range(10):

  #The following is repeated while the current element is greater than 0

while kount[i] > 0:

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greatestNum = greatestNum + ( i * multiplier )

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multiplier = multiplier * 10

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7 0
2 years ago
Serum cholesterol levels of 100 hypertensive patients were recorded. Mean cholesterol level was 190 mg/d1. The data was symmetri
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The standard error is 1.5.

The range of 95% confidence interval is 160 mg/dL and 220 mg/dL

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where N is the number of participants = 100

From the empirical rule of a normal or symmetrical distribution;

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Therefore,  175 mg/dl and 205 mg/dl lie one standard deviation from the mean.

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a. Solving for the standard error using the equation above;

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Range of values two standard deviations from the mean = 190 - (2*15) and 190 + (2 * 15)

Range of values two standard deviations from the mean = 160 mg/dL and 220 mg/dL

Therefore, the range of 95% confidence interval is 160 mg/dL and 220 mg/dL

In conclusion, the standard error is calculated from the standard deviation and the sample size.

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