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timurjin [86]
4 years ago
6

If x+y = z and y−z=x which of the following must be equal to z?

Mathematics
1 answer:
umka21 [38]4 years ago
8 0

<u>ANSWER</u>

(C) y

<u>EXPLANATION</u>

We have two equations:

The first one is

x + y = z...(1)

The second equation is

y - z = x...(2)

Let us make z the subject of this second equation:

\implies \: -x +y = z...(3)

We now add equation (1) and (3) to get:

(-x + x) + (y +  y) = z + z

We simplify to get:

0+2y= 2z

2y= 2z

Divide throu by 2.

\frac{2y}{2}  =  \frac{2z}{2}

y= z

\therefore \: z = y

The correct answer is C

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Answer:

They will deliver on the same day again 21 days later

Step-by-step explanation:

Multiples of 3 and 7

3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

7: 7, 14, 21, 28, 35, 42, 49

They will deliver on the same day again 21 days later

8 0
2 years ago
Three time stue number of blue tiles in a bag is the same as 30% of the number of blue tiles in the bag increased by 54. How man
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A class is planning a trip. The table shows the number of seats, y, based on the number of buses, x.
gtnhenbr [62]
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7 0
3 years ago
Can you explain how to solve this please?
givi [52]

9514 1404 393

Answer:

  -25

Step-by-step explanation:

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  10×10 = 100

  √100 = 10

Then multiply that value by -2.5

  -2.5×10 = -25

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6 0
3 years ago
The following table relates the weights and
MA_775_DIABLO [31]

The probability of randomly chosen tall and obese individuals is 0.30.

Firstly complete the given table and find the total of each row and column.

                 Tall   Medium   Short   Total

Obese             18       28      14  60

Normal           20       51     28         99

Underweight   12       25       9  46

Total          50        104     51 205

We have to find P(Tall | Obese).

P(Tall | Obese) =  P(Tall and Obese) / P(Obese)

Now, P(Tall and Obese) = 18 ÷ 205

And, P(Obese) = 60÷205

Substituting the above values,

P(Tall | Obese) =  18÷205/ 60÷205

P(Tall | Obese) = 18/60

P(Tall | Obese) = 0.30

Hence the probability of a tall and obese individual is 0.30.

To learn more about probability, visit: brainly.com/question/11234923

#SPJ9

8 0
1 year ago
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