Question

The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than 6 months to review; these are omitted from the table. Consider the data to be a population.

Answer 1

A) Variance = 10.24

B) Standard Deviation = 3.2

One of the measurements of dispersion is the standard deviation, which is exclusively used for quantitative data. It aids in determining if the data's mean is a suitable measurement to reflect the core value.

TIME         FREQUENCY(f)  MIDPOINT(x)    d    d²     fd              fd²

0 - 0.9         43                          0.45             -3     9     -129            387

1.0 - 1.9         17                           1.45              -2    4     -34                68

2.0 - 2.9       19                            2.45             -1     1       -19               19

3.0 - 3.9        18                            3.45             0     0       0                  0

4.0 - 4.9        14                            4.45              1      1        14               14

5.0 -5.9         16                            5.45              2     4        32             64                            

∑f = 127                                                              

∑fd = -136  

∑fd² = 552

$d = \frac{x - 3.45}{1}$

Standard Deviation = $\sqrt \frac{fd^{2} }{N} - \sqrt \frac{(fd)^{2} }{N} * i$

$\sqrt \frac{552}{127} -\sqrt (\frac{-136}{127})^{2} * 1$

√4.35 - √1.15

Standard Deviation = 3.2

(SD)² = (3.2)² = 10.24

Variance = 10.24

To know more about standard deviation, refer to this link :

brainly.com/question/12402189

#SPJ1