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allochka39001 [22]
3 years ago
13

Here is a question for all :)

Mathematics
2 answers:
Schach [20]3 years ago
5 0

Answer:

The circle on the far left is the sum of 4x + 3y and 2x - y so the answer is 4x + 3y + 2x - y = 6x + 2y. The circle on the far left is the sum of x + 4y and something. To find that "something" we can do 4x + 5y - (x + 4y) = 3x + y which is the value of the bottom right rectangle. This means that the value of the bottom circle is 2x - y + 3x + y = 5x.

bazaltina [42]3 years ago
4 0

Answer:

Step-by-step explanation:

left circle=4x+3y+2x-y=6x+2y

right  bottom rectangle=4x+5y-(x+4y)=4x+5y-x-4y=3x+y

Bottom circle=2x-y+3x+y=5x

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The first term of a geometric series is -3, the common ratio is 6, and the sum of the series is -4,665 Using a table of values,
vladimir1956 [14]

Answer:

There are 5 terms in the series.

Step-by-step explanation:

S=a\frac{1-r^{n} }{1-r}\\a=-3\\r=6\\-4665=-3\frac{1-6^{n} }{1-6}\\1555=\frac{1-6^{n} }{-5}\\\-7775=1-6^{n}\\6^{n}=7776\\

Take logs to get n = 5

8 0
3 years ago
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Which of the following is a proper fraction 7/6 4/3 1/2 3/3
larisa86 [58]
1/2 because 7/6 & 4/3 are improper fractions(fractions that have a higher numerator than a denominator) and 3/3 should just be written as 1.
4 0
3 years ago
Find the inverse function of y=9x
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Answer:

Replace  

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4 0
2 years ago
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Step-by-step explanation:

4 0
3 years ago
I am trying to graduate HS please help me out!!!
vichka [17]
1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:
<span> 
 A=(b1+b2/2)h
</span><span> 
 A is the area of the trapezoid.
</span><span> b1 is the larger base of the trapezoid (b1=16-4=12 ft).
</span><span> b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
</span><span> h is the height of the trapezoid (h=12-4=8 ft)
</span><span> 
 2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:
</span><span> 
 A=(b1+b2/2)h
</span><span> A=(12 ft+6 ft/2)(8 ft)
</span><span> A=9 ftx8ft
</span><span> A=72 ft² 
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6 0
3 years ago
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