Answer:
The flagpole's shadow is 16.875 feet longer than the man's shadow
Step-by-step explanation:
The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;
Height of the shadow=actual height of the flagpole×factor
where;
length of the flagpole's shadow=22.5 feet
actual height of the flagpole=32 feet
factor=f
replacing;
22.5=32×f
32 f=22.5
f=22.5/32
f=0.703125
Using this factor in the expression below;
Length of man's shadow=actual height of man×factor
where;
length of man's shadow=m
actual height of man=8 feet
factor=0.703125
replacing;
length of man's shadow=8×0.703125=5.625 feet
Determine how much longer the flagpole's shadow is as follows;
flagpoles shadow-man's shadow=22.5-5.625=16.875 feet
The flagpole's shadow is 16.875 feet longer than the man's shadow
Answer:
there
Step-by-step explanation:
Answer:
Step-by-step explanation:
We want to combine alike terms so
-2/3c+14c & -9/5+3/10
14c-2/3
Multiply 14/1 by 3/3 to get the denominators the same
Subtract
simplify
now
Multiply 9/5 by 2/2
Subtract
Simplify
put both together
Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!
He has done 70 push ups because by the 15th he has done 35 push ups add 15 more days and u get 70 .
Answer:
40°
Step-by-step explanation:
Because triangle QSR is isosceles ∠SQR=∠SRQ=35°. The sum of the angles in a triangle is 180°, so ∠QSR=180°-35°-35°=110°. The measure of a straight line is 180°, so ∠PSQ=180°-110°=70°. Because triangle PSQ is also isosceles ∠PSQ=∠PQS=70°. Then, ∠QPS=180°-70°-70°=40°.
