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Vedmedyk [2.9K]
2 years ago
15

Find the missing side length 5m x

Mathematics
1 answer:
galben [10]2 years ago
8 0

Answer:

There is not enough information for me to answer this question. However, since the area is not shown, the missing side length can be any positive number. AKA, infinity.

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Please help me I am confused
nadezda [96]

Answer: X= 11

Step-by-step explanation:

3 0
3 years ago
Does 26/3 equal 182/21
brilliants [131]

Answer: Yes, they are equal

Step-by-step explanation:

Quick statement: To find equivalent fractions, multiply or divide them by the same number.

In this particular example, you can divide 182 by 7 and get 26 and 21 by 7 to get 3. This symbols that they are equal. If you try the inverse operation (multiplication), you could multiply 26 by 7 and get 182. Same goes for 21 and 3: you multiply 3 by 7 to get 21. Just remember to multiply or divide the two numbers (numerator and denominator) by the same number to get an equivalent fraction.

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Does anyone understand I really dont get this
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3 years ago
Drew needs to air up his teams 8 soccer balls. Each ball has a diameter of 70cm. In terms of pi, what is the total volume of air
Liula [17]

Answer:

1.44m^3

Step-by-step explanation:

Given data

Number of balls= 8

Diameter of ball = 70cm = 0.7m

Radius= 35cm= 0.35m

We know that a ball has a spherical shape

The volume of a sphere is

V= 4/3πr^3

substitute

V= 4/3*3.142*0.35^3

V= 0.18m^3

Hence if 1 ball has a volume of 0.18m^3

Then 8 balls will have a volume of

=0.18*8

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7 0
3 years ago
Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num
Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be  m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is  ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg  = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0
3 years ago
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