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Digiron [165]
4 years ago
15

Which of these is an example of continuous random variable?

Mathematics
1 answer:
Nana76 [90]4 years ago
4 0

Answer:

B. weight of a bag of apples

Step-by-step explanation:

A continuous random variable is a variable that is measured not counted. It can be any number between integers in decimal form.

So from the options given above, only the weight of bag of apples is a continuous variable as it will be measured.

While the others cannot be expressed in the form of decimals.

So the correct answer is:

B. weight of a bag of apples ..

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Solve for R. 3 + 3r > 9
Nostrana [21]

Answer:

r > 2

Step-by-step explanation:

9-3 = 6

6/3 = 2

Have a good day :)

7 0
3 years ago
Mrs. Nestler enjoys listening to classical music. She has the following audio CDs by her favorite composers in her collection: 4
ivolga24 [154]

Answer:

10.55% probability

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the CDs are chosen is not important. So we use the combinations formula to solve this question.

1 Bach CD, from a set of 4.

1 Beethoven CD, from a set of 6.

1 Brahms CD, from a set of 3.

1 Handel CD, from a set of 2.

So, D=144

4 CDs from a set of 4+6+3+2 = 15.

So, T= 1365

p= D/T= 144/1365 = 0.1055

10.55% probability that she will choose one by each composer

4 0
3 years ago
In a triangle, what is true about the sum of the lengths of any two sides of the triangle?
irakobra [83]
It will be greater than the length of the third side always
4 0
4 years ago
Read 2 more answers
pllllllls I need help right triangle and trigonometry special right triangles find the value of each variable​
yanalaym [24]

\huge {\mathfrak{Answer :  }}

we know,

\boxed{\cos( \theta)  =  \dfrac{base}{hypotenuse}}

so,

  • \cos(30)  =  \dfrac{24}{x}

  • \dfrac{ \sqrt{3} }{2}  =  \dfrac{24}{x}

  • x =  \dfrac{24 \times 2}{ \sqrt{3} }

  • x = 8 \sqrt{3}  \times 2

  • x = 16 \sqrt{3}

now,

\boxed{ \tan( \theta) =  \frac{perpendcular}{base}  }

  • \tan(30)  =  \dfrac{y}{24}

  • \dfrac{1}{ \sqrt{3} }  =  \dfrac{y}{24}

  • y =   \dfrac{24}{ \sqrt{3} }

  • y = 8 \sqrt{3}
6 0
3 years ago
Which illustrates the construction of a perpendicular to a line from a point on the line?
quester [9]
I believe the correct answer from the choices listed above is the last option. The last option clearly describes the illustration of the construction of a perpendicular to a line from a point on the line where you start on a point in the line. Using an arbitrary radius, draw arcs intersecting the line <span> at two points. </span>
Hope this answers the question. Have a nice day.
6 0
3 years ago
Read 2 more answers
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