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anygoal [31]
2 years ago
14

I need help please!!!

Mathematics
1 answer:
Phoenix [80]2 years ago
4 0

9514 1404 393

Answer:

  (a) ∠3 and ∠5, or ∠4 and ∠6

  (b) ∠1 and ∠5, or ∠2 and ∠6, or ∠3 and ∠7, or ∠4 and ∠8

  (c) ∠1 and ∠7, or ∠2 and ∠8

Step-by-step explanation:

This is basically a vocabulary question. The words more less mean the following:

  alternate - on opposite sides of the transversal

  interior - between the parallel lines

  exterior - outside the parallel lines

  corresponding - in the same direction from the point of intersection

__

We can say this about the angles of interest with respect to the angle numbering shown. (Angles are not always numbered this way.)

(a) Alternate interior angles - interior angles whose numbers add to give 8 or 10. ∠3 and ∠5, or ∠4 and ∠6

__

(b) Corresponding angles - angles whose numbers differ by 4.

  ∠1 and ∠5, or ∠2 and ∠6, or ∠3 and ∠7, or ∠4 and ∠8

__

(c) Alternate exterior angles - exterior angles whose numbers add to give 8 or 10. ∠1 and ∠7, or ∠2 and ∠8

_____

<em>Additional comment</em>

All of these pairs of angles are congruent pairs. You will see this means all acute angles are congruent, and all obtuse angles are congruent (when the lines are parallel). Of course, the obtuse and acute angles are supplementary. (There is additional nomenclature describing those supplementary pairs.)

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Problem 3
Murljashka [212]

Answer:

-\frac{2}{5}

Step-by-step explanation:

Given expression:

           2x + 5y = -10

The equation of a straight line is;

            y = mx + c

y and x are the coordinates

m is the slope

c is the intercept

 Now;

          let us write the given expression in slope intercept format;

            2x + 5y  = -10

                    5y = -2x - 10

                     y = -\frac{2x}{5}  - 2

So, the slope of the line is -\frac{2}{5}

8 0
2 years ago
A line has a slope of -2/5 and passes through the point (10,7) . Write the equation of this line in point-slope form, slope-inte
qaws [65]

(\stackrel{x_1}{10}~,~\stackrel{y_1}{7})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{-\cfrac{2}{5}}(x-\stackrel{x_1}{10})

6 0
1 year ago
[someone help] The speed of the object 7 seconds after it is dropped is ___m/sec
nadezda [96]

9514 1404 393

Answer:

  68.6 m/s

Step-by-step explanation:

The speed at a given time is the derivative of the height at that time.

  dh/dt = -9.8t

At t=7, the speed is ...

  -9.8(7) = -68.6 . . . . . meters per second (downward)

The speed is 68.6 meters per second.

_____

<em>Additional comment</em>

Height is considered to be positive in the up direction, so velocity and acceleration are also positive in the up direction. The derivative of height will be the velocity. Its negative sign in this case indicates the object is moving in the downward direction. The speed is the magnitude (absolute value) of the velocity.

3 0
3 years ago
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