the frequency of the sinusoidal graph is 2 in 2 π interval
Step-by-step explanation:
The frequency of the graphs refers to the number of the cycles, the graph completes in a given fixed interval.
We already know the formula that
P= (1/ F)
Thus, F= (1/ P)
Where F= frequency and P= Period
Period is the horizontal length (x- axis component) of one complete cycle.
Thus, Observing the above graph
We find that the graph completes 1 cycle in π interval and 2 cycles in 2π interval
Thus, the frequency of the sinusoidal graph is 2 in 2 π interval
C=πd
r=21
d=42
C=132 ft, and D is your final answer. Hope it help!
angle EPF = angle DPG
=> 4x + 48deg = 7x
=> 3x = 48 deg
=> x = 16
=> angle EPF = 4(16) +48 = 112deg
2x+8y=-32
8y=-2x-32
y=-1/4x-4
The slope is -1/4, the y-intercept is -4, and I can't graph it for you on here. Type my equation into a graphing calculator and it'll do it for you. (Desmos is a good online graphing calc, and it's free)
Answer:
k(3n) = 9n² + 9n
General Formulas and Concepts:
Order of Operations: BPEMDAS
- Substitution and evaluation
Step-by-step explanation:
<u>Step 1: Define</u>
k(n) = n² + 3n
k(3n) is n = 3n
<u>Step 2: Solve</u>
- Substitute: k(3n) = (3n)² + 3(3n)
- Exponents: k(3n) = 9n² + 3(3n)
- Multiply: k(3n) = 9n² + 9n
