The information given about the proof does that Daniel made an error on line 2.
<h3>How to illustrate the information?</h3>
Given:
1. AB = 3x +2; BC = 4x + 8; AC = 38
2. AB + BC = AC incorrect (not an angle angle addition postulate)
3. 3x+2 + 4x + 8 = 38 correct
4. 7x + 10 = 38 correct
5. 7x = 28 correct
6. x = 4
Daniel made an error on line 2.
Here is the complete question:
Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5
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Answer:
8
Step-by-step explanation:
The given expression is "three less than the quotient of ten and a number, increased by six”
The quotient of ten and a number increased by six is translated into mathematical expression as:

Three less than the quotient of ten and a number, increased by six is

When we substitute n=2, we get:

Divide to get:

Add to get:

Subtract

Answer:
is there like a image of this eqation?
Step-by-step explanation:
Answer:
<h2>x = 3.1</h2>
Step-by-step explanation:
<h3>

</h3>
<u>To solve first take logarithm to both sides</u>
That's
<h3>

</h3><h3 /><h3>

</h3>
But
<h3>

</h3>
So we have

<u>Write 1200 as a number with the factor 100</u>
That's
1200 = 100 × 12
So we have
<h3>

</h3>
<u>Using the rules of logarithms</u>
That's
<h3>

</h3>
Rewrite the expression
That's
<h3>

</h3><h3 /><h3>

</h3><h3>

</h3><h3>

</h3><h3 /><h3>

</h3>
x = 3.079
So we have the final answer as
<h3>x = 3.1 to one decimal place</h3>
Hope this helps you