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Cerrena [4.2K]
3 years ago
10

Neeeeeeeeeed helppppppppppppp

Mathematics
1 answer:
Serhud [2]3 years ago
5 0
D)
Because Mexico borders the US, but it does not border Canada. The conditional is false.
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PLEASE HELP!
alexdok [17]

Answer:

1. >

2. <

3. =

Step-by-step explanation:

100x8=800, 4*7=28, multiplied by 25 is 700, therefore making 800 greater than 700. Whenever comparing two multiplication problems, multiplying large numbers produces large results, so whichever starts larger will have an end result that is larger. 100 was large and it is smaller to its counter 25.

36 elevens really means 11x36, which is 396. 40 elevens really means 40x11, which is 440 minus 11x3 which is 407. 407 is greater than 396. The same logic applies here as the previous answer, the only difference is that the removal of three elevens is still larger than 36 elevens in this case.

12x24=288, 6x24=144, doubled makes it 288. In this case, the six is half of the twelve to begin with and then is made up for later by the fact that it is doubled.

When I solve math questions like these, I ignore the fact that it doesn't want a mathematical answer, do the math anyway and pull logic from it. (If your teacher checks, do it on a separate piece of paper, and then toss it.)

5 0
3 years ago
One more math question! Thanks!
alisha [4.7K]
The answer is 50. no guarantee  this is.
5 0
3 years ago
Read 2 more answers
Help with this question, ASAP!!
Taya2010 [7]

Answer:

The answer to your question is: second option

Step-by-step explanation:

g(x) = x + 4

- This function is linear because the power of x is 1, if the power were a different number it would not be linear.

- As the sign of 4 is positive, it means that the function is translated 4 units up.

- A constant is when there is a number, for example +4 or -4, in this example the function also has a letter "X" so it is not a constant.

7 0
3 years ago
????????????????????
Shtirlitz [24]
It’s a diagram ur welcome
3 0
3 years ago
In how many distinct ways can the letters of the word mathematics be arranged? (first, does the order matter?)
TEA [102]
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).

Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
4 0
3 years ago
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