Answer:
I do not know, but I do know the formula.
The formula is: 12pl+B where p represents the perimeter of the base, l the slant height and B the area of the base.
Find an equation of the plane that passes through the points p, q, and r. p(7, 2, 1), q(6, 3, 0), r(0, 0, 0)
Alona [7]
Answer:
x - 2y - 3z = 0
Step-by-step explanation:
The cross product of vectors rp and rq will give a vector that is normal to the plane:
... rp × rq = (-3, 6, 9)
Dividing this by -3 (to reduce it and make the x-coefficient positive) gives a normal vector to the plane of (1, -2, -3). Usint point r as a point on the plane, we find the constant in the formula to be zero. Hence, your equation can be written ...
... x -2y -3z = 0
Answer:
Where?
Step-by-step explanation:
Given that the equation of the line is:
y=-18x-2
the equation is in the form of y=mx+c, where m is the slope. Thus the slope of equation is -18. The line perpendicular to this equation has a slope of 1/18, hence the equation will be given by the formula:
m(x-x1)=y-y1
given that the line passes through point (-2,-3) the equation of the line will be:
1/18(x--2)=y-(-3)
1/18(x+2)=y+3
simplifying this gives us:
y=1/18x+1/9+3
y=1/18x6+3 1/9
