-6(x-3)+4x simplify the expression
2 answers:
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Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable:
Therefore,
Variance of binomial random variable:
Therefore,
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.