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emmainna [20.7K]
2 years ago
6

-6(x-3)+4x simplify the expression

Mathematics
2 answers:
monitta2 years ago
5 0

Answer:

-2x + 18

Step-by-step explanation:

Simplfy

-6 (x - 3) + 4x

-6x + 18 + 4x         Combine liked terms

-2x + 18

kobusy [5.1K]2 years ago
3 0

Answer: -2x+18

Hope this will help :)

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Is the relation in this set of points a function
natita [175]
It is not a function—an element from the domain is paired with more than one element from the range. Specifically, the input value of 4 corresponds to two output values: 5 and -4.

A function can only take on one output for each input. It only takes one input value to associate with more than one output value to be invalid as a function.

Please mark this answer as the Brainliest, if you find this helpful :)
7 0
2 years ago
Determine the volume of the parallelepiped with one vertex at the origin and the three vertices adjacent to it at (2, â1, â1), (
valentinak56 [21]

Answer:

23

Step-by-step explanation:

Here is the complete question

Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).

Solution

We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.

So, (1, 0, -3), (1, 2, 4)  and (5, 1, 0)

A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]

The determinant of A is the volume of the parallelepiped. So,

detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)

= 1(0 - 4) - 1(0 + 3) + 5(0 + 6)

= 1(-4) - 1(3) + 5(6)

= -4 - 3 + 30

= 23

So the volume of the parallelepiped is 23

4 0
2 years ago
No one was born ugly<br> we just live in a judgmental world
bogdanovich [222]

Answer:

Ikr >:(

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Find lim x-&gt;2 for f(x)=
TiliK225 [7]

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

8 0
1 year ago
Help me please I dont know what to do
gtnhenbr [62]

Answer:

It's <u>option A. ± </u>√6<u>0</u>

Step-by-step explanation:

x^2  = 60

here ^2 will move to the other side and when it does it'll become a square root to 60.

so, x = √60

now, the answer in its simplified form would be 2√15 and -2√15.

The answer of this square root will be negative as well as positive, so, ±√60.

3 0
2 years ago
Read 2 more answers
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