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oksano4ka [1.4K]
3 years ago
12

Anyone know answer?!

Mathematics
2 answers:
alina1380 [7]3 years ago
8 0
The slope is negative
Lostsunrise [7]3 years ago
6 0
B. the slope is negative
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3/4 x 144 = 108
108 x 5/9 = 60

B. 60 female students voted for you.
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Can someone please tell me what I need to do and possibly help me answer this I am so confused
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It's b. Group all the pounds together and all the volumes together. Small packages weigh 30 lbs (30x), lg pkgs weight 65 lbs (65y) and together they weigh at most 3800 lbs. So 30x + 65y <= 3800 (they divided each of those terms by 5 to get 6x + 13y <= 760). Next take the volumes: small pkgs have a volume of 4 ft^3 (4x) and lg pkgs have a volume of 9 ft^3 (9y) and together they are no more than 400 ft^3. So 4x + 9y <= 400.  It's b.
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3 years ago
At a local grocery store, hamburger meat is normally $3.50 per pound, but this week hamburger meat is on sale for $2.10 per poun
AysviL [449]

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A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m
zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= t_{n-1: 1-\alpha/2} * (\frac{S}{\sqrt{n} })

I've  cleared the sample size of the formula

n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025}  = t_{4;0.975} =2.776

n= (19.62*\frac{2.776 }{8} )^{2}

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005}  = t_{4;0.995} =4.604

n= (19.62*\frac{4.604}{8} )^{2}

n= 127.49 ≅ 128

I hope it helps!

4 0
3 years ago
26. Which of the following DO NOT illustrates independent events?
AlexFokin [52]

Answer:

  C. obtaining an even number when rolling a die

Step-by-step explanation:

Two events are independent when neither depends on the other. That is, the probability that one occurs is not affected by the occurrence, or lack of occurrence, of the other event. Their joint probability is the product of their individual probabilities.

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Among the answer choices, all describe two independent events except C. Choice C describes one (1) event, so does NOT illustrate independent events.

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