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2 years ago

Is this graph increasing or decreasing or is it constant ?

Mathematics

2 answers:

lesya [120]2 years ago

8 0

Answer:

option B. constant

Step-by-step explanation:

In the graph attached there is a straight line parallel to x-axis that is y = 3.

Intercept form of a line is given by y = mx + c

where m = slope of the line

c = y-intercept

When we compare the line y = 3 to the intercept form of the equation we find m = 0, so this line is parallel to x-axis.

and y = 3 is constant.

Therefore, option B. constant is the answer.

Gwar [14]2 years ago

7 0

Constant because of the fact that it has a zero slope, so it will never decrease nor decrease.

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Please help and show steps

Sonja [21]

Answer:

i think it is c sorry if wrong

Step-by-step explanation:

4 0

3 years ago

Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so

xeze [42]

Answer:

She can only make 5/6 of her recipe with the amount of milk that she has.

Step-by-step explanation:

Some data of this problem is missing, the data missing is:

Her recipe calls for 3/4 of a pint of milk and she only has 5/8 of a pint of milk.

Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:

$\frac{5}{8}$ ÷ $\frac{3}{4}$

When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:

$\frac{5}{8}$ ÷ $\frac{3}{4}=\frac{5}{8}$ × $\frac{4}{3} =\frac{20}{24}$

If we simplify this last expression we have:

$\frac{20}{24}=\frac{10}{12} =\frac{5}{6}$

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.

<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>

6 0

3 years ago

(01.04)

Ymorist [56]

Answer:2

Step-by-step explanation: the equation is in linear form y=mx+b, the b represents the y intercept in your equation that would be -5

5 0

3 years ago

What number is divisible by both 85 and 51

Vitek1552 [10]

17
85/17 is 5 and 51/17 is 3

7 0

2 years ago

Read 2 more answers

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

2 years ago