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3 years ago

Please help!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Viefleur [7K]3 years ago

6 0

Answer:

y = 2/3x + 4

Step-by-step explanation:

Slope-intercept form of a line:

y = mx + b

where m = slope and b = y-intercept

To find the equation of a line, we need two points that the line passes through.

We can use the x-intercept and y-intercept of the line: (-6,0) and (0,4), respectively.

Find the slope of the line using these two points:

Slope formula:

Plug the two points into the formula.

Subtract and simplify this fraction.

The slope of this line is m = 2/3.

Now we can look at the graph to determine the y-intercept of this line; the line intersects the y-axis at (0,4) so the constant b = 4.

We can use the slope, m, and the y-intercept, b, and substitute these values into the slope-intercept form of a line.

y = 2/3x + 4

The equation of the line is y = 2/3x + 4.

Andrej [43]3 years ago

3 0

Answer:

y = 2/3x + 4

Step-by-step explanation:

Slope-intercept form of a line:

y = mx + b
where m = slope and b = y-intercept

To find the equation of a line, we need two points that the line passes through.

We can use the x-intercept and y-intercept of the line: (-6,0) and (0,4), respectively.

Find the slope of the line using these two points:

Slope formula: $\displaystyle \bf \frac{y_2-y_1}{x_2-x_1}$

Plug the two points into the formula.

$\displaystyle \frac{4-0}{0-(-6)}$

Subtract and simplify this fraction.

$\displaystyle \frac{4}{6} =\frac{2}{3}$

The slope of this line is m = 2/3.

Now we can look at the graph to determine the y-intercept of this line; the line intersects the y-axis at (0,4) so the constant b = 4.

We can use the slope, m, and the y-intercept, b, and substitute these values into the slope-intercept form of a line.

y = 2/3x + 4

The equation of the line is y = 2/3x + 4.

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3 years ago

Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?

BaLLatris [955]

Answer:

$Vertex = (\frac{1}{2},\frac{7}{4})$

Step-by-step explanation:

Given

$f(x) = x^2 - x +2$

Required

The vertex

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$f(x) = x^2 - x +2$

First, we express the equation as:

$f(x) = a(x - h)^2 +k$

Where

$Vertex = (h,k)$

So, we have:

$f(x) = x^2 - x +2$

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

$f(x) = x^2 - x +2$

$f(x) = x^2 - x + (-\frac{1}{2})^2+2 -(-\frac{1}{2})^2$

$f(x) = x^2 - x + \frac{1}{4}+2 -\frac{1}{4}$

Expand

$f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2 -\frac{1}{4}$

Factorize

$f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2 -\frac{1}{4}$

Factor out x - 1/2

$f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}$

Compare to: $f(x) = a(x - h)^2 +k$

$h = \frac{1}{2}$

$k = \frac{7}{4}$

Hence:

$Vertex = (\frac{1}{2},\frac{7}{4})$

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