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laila [671]
3 years ago
14

Tracy McKinney is a disc jockey at radio station WMMM. Her annual salary is $52,750. What is her monthly salary?

Mathematics
1 answer:
attashe74 [19]3 years ago
5 0
Okay, so since her annual salary is <span>$52,750 (the amount she gets a year, all twelve months combined) you're trying to find how much she gets monthly. That would mean we would have to divide her annual salary by 12 to find her monthly salary.

</span>$52,750 ÷ 12 = 4,395.8333333333333
<span>
And since that's a (bothersome) repeating decimal, we're going to have to round it. Once rounded, you would get $</span>4,395.83. That is her monthly salary.
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What three consecutive integers equal -87?
olchik [2.2K]

Answer:

What three consecutive integers have a sum of 87? Which means that the first number is 28, the second number is 28 + 1 and the third number is 28 + 2. Therefore, three consecutive integers that add up to 87 are 28, 29, and 30. We know our answer is correct because 28 + 29 + 30 equals 87 as displayed above.

Step-by-step explanation:

Consecutive integers are as simple as 1, 2, 3!  

Integers are consecutive if one follows another.  How do we "jump" from one integer to the next?  We add 1, right?  7, 8 and 9 are three consecutive integers.  Add one to 7 to get 8 and add one more to get 9.

Now lets think about this in algebraic terms.  Lets name these consecutive integers , x, y and z.  

The problem tells us that their sum is -87.  (Recall, "sum" is just a fancy word for the answer when we add.)

x+y+z = -87  

Here is the trick!  We need to rewrite this equation so that we have only one variable.  Easy!

y is one more that x, so y= x+1

And z is one more than y, so z= y+1.  But y is also equal to (x+1)!  So z=y+1=(x+1)+1=x+2

Now we have a problem that we can solve!  x+(x+1)+(x+2)=-87.  

Combining term.:  3x+3=-87  

Subtract 3 from both sides of the equation:  3x=84

Divide each side of the equation by 3:  x=28

We have solved for x, but we are not done!  We need to find y and z.  I know you can do this.  Remember y is one more than x and z is one more than y.

Check your work!  Make sure these three consecutive numbers do in fact add up to -87.

4 0
3 years ago
Is the function linear or quadratic?
fgiga [73]

It is quadratic since a quadratic function is of the form :y=ax²+bx+c ,a,b,c are constants.

7 0
4 years ago
Simplify: (–4) • (9) – (5) • (–2) (A)2 (B)–36 (C)–26 (D)82
Lorico [155]
(C) -26 because you have use PEMDAS
3 0
3 years ago
Read 2 more answers
Harry solves the equation 1/3t = 15. He says the solution is 30. Is his answer correct? Fill in the blanks to explain how Harry
aksik [14]

Harry can first substitute 30 for t

He can then multiply \frac{1}{3} by 30 to get a product of 10

Since, 10 is not equal to 15, Harry's solution is not correct.

<em><u>Solution:</u></em>

Given that,

Harry solves the equation:

\frac{1}{3}t = 15

He says the solution is 30

We have to check if his answer is correct or not

<em><u>Fill in the blanks to explain how Harry can check whether his solution is correct</u></em>

Harry can first substitute 30 for t

\frac{1}{3} \times 30 = 15

He can then multiply \frac{1}{3} by 30 to get a product of 10

10\neq 15

Since, 10 is not equal to 15, Harry's solution is not correct

<em><u>Correct solution:</u></em>

\frac{1}{3}t = 15\\\\t = 15 \times 3\\\\t = 45

Thus correct solution is 45

5 0
3 years ago
Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Supersc
MAVERICK [17]

Answer:

\displaystyle \frac{5x}{8y^{4}}\sqrt{x}

Step-by-step explanation:

<u>Simplfy in Algebra </u>

We have the following expression

\displaystyle E=\sqrt{\frac{25x^9y^3}{64x^6y^{11}}}

Simplifying like factors in the denominator and numerator

\displaystyle E=\sqrt{\frac{25x^3}{64y^{8}}}

All the factors are perfect squares except x^3, thus we rewrite:

\displaystyle E=\sqrt{\frac{25xx^2}{64y^{8}}}

Taking the square root of all the perfect square factors:

\boxed{\displaystyle E=\frac{5x}{8y^{4}}\sqrt{x}}

5 0
3 years ago
Read 2 more answers
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