Answer:
40%
Step-by-step explanation:
From the given statements:
The probability that it rains on Saturday is 25%.
P(Sunday)=25%=0.25
Given that it rains on Saturday, the probability that it rains on Sunday is 50%.
P(Sunday|Saturday)=50%=0.5
Given that it does not rain on Saturday, the probability that it rains on Sunday is 25%.
P(Sunday|No Rain on Saturday)=25%=0.25
We are to determine the probability that it rained on Saturday given that it rained on Sunday, P(Saturday|Sunday).
P(No rain on Saturday)=1-P(Saturday)=1-0.25=0.75
Using Bayes Theorem for conditional probability:
P(Saturday|Sunday)=
=
=0.4
There is a 40% probability that it rained on Saturday given that it rains on Sunday.
The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
------------------
6x^2y^3
= 2( 5y^2 - 2x)
-----------------
6x^2y^3
= 5y^2 - 2x
-----------
3x^2y^3
Answer:
21, 35 , 49
Step-by-step explanation:
21 = 3 * 7
35 = 5 * 7
49 = 7 * 7
GCF = 7
189 because 20.7 rounds to 21 and 9.18 rounds to 9
21 * 9 = 189
Divide both sides by :
Substitute , so that .
Multiply both sides by :
The left side can be condensed into the derivative of a product.
Integrate both sides to get
Solve for :
Solve for :