All categories

3 years ago

Hurry I’ll give 10pts

Mathematics

1 answer:

balandron [24]3 years ago

4 0

The answer to the question is a

You might be interested in

The formula for the volume of a cube is V = s³, where s represents the side length of the cube. If a cube has a side length of 4

Alla [95]

Answer:

91.125 or 729/8

Step-by-step explanation:

take 4.5^3 to get 91.125

7 0

3 years ago

Read 2 more answers

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?

Eva8 [605]

$\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6} }} \huge{) } \small{{}^{ {}^{ {}^{ {}^{ - 2} } } } }\\ \\ \\ \huge{(} \small{ \frac{4 \times m {}^{1} \times n {}^{1} }{ {m}^{ - 2} \times {n}^{6} }} \huge{)} \small{^{ {}^{ {}^{ {}^{ - 2} } } }} \\ \\ \\ \huge{(} \small{4 \times {m}^{1 - ( - 2)} \times {n}^{1 - 6}} \huge{)} \small{ {}^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \huge{(} \small{ 4 \times {m}^{1 + 2} \times {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \small{ {(4)}^{ - 2} \times ({m}^{3} ) ^{ - 2} \times {(n{}^{ - 5} )}^{ - 2} } \\ \\ \\ \frac{1}{ {4}^{2} } \times {m}^{ - 6} \times {n}^{ 10} \\ \\ \\ \frac{1}{16} \times \frac{1}{ {m}^{6} } \times {n}^{10} \\ \\ \\ \frac{ {n}^{10} }{16{m}^{6} }$

$\text{ Hence, option B is correct }$

7 0

3 years ago

Find the perimeter of the larger polygon if the two polygons are similar.

Lilit [14]

Answer:

130.5

Step-by-step explanation:

similar shapes have proportional sides so divide 18/27 to get the proportion then multiply each side of the smaller polygon by the proportion to get the sides for the larger polygon and add the larger polygons sides together.

8 0

3 years ago

True or false?is the point(16,4) included in this function: Y=2x or Y=x2 or y= x+12 or y=x-12

Gelneren [198K]

Answer:

True

Step-by-step explanation:

It is true because the graph of $y=x-12$ passes through the point $(16,4)$

x = 16

y = 4

Substitute

4 = 16 - 12

4 = 4

Therefore, the answer is true.

8 0

2 years ago