If P(A) = 1/10 , find P(A)

I need help. Of the make sense of the problem section. Please

uranmaximum [27]

the basket balls height when bounced can vary. depending on the strength of ball being thrown to the ground can make the ball bounce even higher. So for an example, if you applied full force from a average weighted male adult. The basket ball will bounce a decent height. But, of course will for sure not be as high as to the first bounce.

hope this helps

5 0

2 years ago

Which solid has a greater volume

Triss [41]

Answer:

The volume of cylinder and the volume of a cone, have equal volume measurements. So, the answer is C).

Step-by-step explanation:

Cylinder:

-Use the formula for the volume of a cylinder. Use both the radius and height for the formula in order to solve and get the volume:

$V = \pi r^2 h$

$V = \pi 2^2 6$

-Solve:

$V = \pi 2^2 6$

$V = \pi \times 2^2 \times 6$

$V = \pi \times 4 \times 6$

$V = \pi \times 24$

$V = 24\pi \approx 75.39$

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Cone:

-Use the formula for the volume of a cone and the radius and height for the formula and solve the formula to get the volume:

$V = \frac{1}{3} \pi r^2h$

$V = \frac{1}{3} \pi 3^28$

-Solve:

$V = \frac{1}{3} \pi 3^28$

$V = \frac{1}{3} \times \pi \times 3^2 \times 8$

$V = \frac{1}{3} \times \pi \times 9 \times 8$

$V = \frac{1}{3} \times \pi \times 72$

$V = \frac{1}{3} \pi \times 72$

$V = 24\pi \approx 75.39$

-So, according to the volume of a cylinder and the volume of a cone, They both have the same volume.

Cylinder: $75.39$ $ft^3$

Cone: $75.39$ $ft^3$

5 0

2 years ago

Evaluate the expression 3x2t when t is 1

JulsSmile [24]

Hey there!

The answer to your question is 6.

To solve this equation when t = 1, we can simply plug t into the equation.

3 x 2(1)

3 x 2

5

Hope this helps your assignment! Have a great day! Good luck!

3 0

2 years ago

) the top and bottom margins of a poster are 4 cm and the side margins are each 5 cm. if the area of printed material on the pos

grin007 [14]

If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)

Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm

The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.

_____
In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.

8 0

3 years ago

The flight path of a plane is a straight line from city J J to city K K. The roads from city J J to city K K take the long way a

Vika [28.1K]

Answer:

58.1 degrees

Step-by-step explanation:

Given the following

JK = 9.4miles (towards south) negative y axis

If the move 15.1 miles towards east (that will be towards the positive x axis)

Using the SOH CAH TOA identity

opposite= 15.1 miles(side facing m<J)

adjacent= JK = 9.4miles

tan theta = opposite/adjacent

tan m<J = 15.1/9.4

tan m<J = 1.6063

m<J = arctan (1.6063)

m<J = 58.09 degrees

Hence the measure of m<J to the nearest tenth is 58.1 degrees

4 0

2 years ago