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3 years ago

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A group of researchers wants to know whether graduates from different teacher preparation programs are more likely to stay in th

e profession. They select a stratified random sample of this year's graduates from several programs. The researchers will contact the graduates after 1, 5, and 10 years to see whether they are teaching in those years.

Advanced Placement (AP)

1 answer:

salantis [7]3 years ago

3 0

Answer:

A prospective study

Explanation:

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Explain the impact that colonialism and imperialism has had on cultural landscapes.

pav-90 [236]

Answer:The rightsof the population were taken in favor of the colonizers

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2 years ago

HEYY I NEED HELP WITH AN AP CALC ASSIGNMENT ASAP

Vladimir79 [104]

CALCULATOR PART

1. The area of R + S is unsigned, meaning you want to find

$\displaystyle\int_a^b\left|f(x)-g(x)\right|\,\mathrm dx$

where $[a,b]$ is the interval between the leftmost and rightmost intersections of $f$ and $g$ .

First use your calculator to find these intersections:

$\cos x=\dfrac{x+1}3\implies x\approx-3.64,x\approx-1.86,x\approx0.889$

so that $a=-3.64$ and $b=0.889$ . Now compute the integral using your calculator:

$\displaystyle\int_a^b\left|f(x)-g(x)|\,\mathrm dx\approx1.662$

2. The volume, using the washer method, is given by the integral

$\displaystyle\pi\int_{-1.86}^{0.889}(|2-g(x)|^2-|2-f(x)|^2)\,\mathrm dx\approx12.078$

3. A circle of radius $r$ has area $\pi r^2$ ; a semicircle with the same radius thus has area $\frac{\pi r^2}2$ . Each cross section of this solid is a semicircle whose diameter is the vertical distance between $f(x)$ and $g(x)$ , or $|f(x)-g(x)|$ . In terms of the diameter $d=2r$ , the area of each semicircle would be $\frac{\pi d^2}8$ . Then the volume of the solid is

$\displaystyle\frac\pi8\int_{-3.64}^{-1.86}|f(x)-g(x)|^2\,\mathrm dx\approx0.0425$

NON-CALCULATOR PART

4. The mean value theorem says that for a function $F$ continuous on an interval $[a,b]$ and differentiable on $(a,b)$ , there is some $c\in(a,b)$ such that

$F'(c)=\dfrac{F(b)-F(a)}{b-a}$

If this $F$ happens to be an antiderivative of $f$ , then we end up with

$f(c)=\displaystyle\frac1{b-a}\int_a^bf(x)\,\mathrm dx$

$\cos x$ is continuous and differentiable everywhere, so the MVT applies. We have $F'(x)=f(x)=\cos x$ , so the MVT tells us there is some $c\in[0,\pi$ such that

$\cos c=\dfrac{\sin\pi-\sin0}{\pi-0}=0$

That is, the average value of $f(x)$ on $[0,\pi]$ is 0. The MVT says there is some $c$ in the interval such that the function takes on the average value itself; this happens for $c=\frac\pi2$ .

5. This question seems to be incomplete...

5 0

4 years ago

Which of the following conditions might typically cause a dog to chew or shred household objects? A. Infestation of parasites B.

Oduvanchick [21]

Hello There

Answer: <span>Prolonged absence of human caretakers (B)

Reason: Dogs need attention and when that isn't given to them they try to entertain themselves by chewing on different objects.

I hope this helps
-Chris</span>

6 0

3 years ago

Read 2 more answers

Helen is a prosecutor. She has tried to convince the grand jury that there is probable cause to believe that Eric, an accused, h

Vladimir79 [104]

d would be the best response for this question.

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3 years ago

ASAP HURRY Drag the descriptions of each investment in order from which will earn the least simple interest to which will earn t

Nady [450]

The descriptions of each investment from least to greatest are:

An investment of 1,200 at a 6% interest rate for 9 years- A = $1,848.00.
An investment of 1,200 at a 12% interest rate for 5 years- A = $1,920.00.
An investment of 1,200 at a 12% interest rate for 9 years - A = $2,496.00.

<h3>What is the investment about?</h3>

An investment of 1,200 at a 12% interest rate for 5 years will be:

I = A - P = $720.00

Note that:

A = P(1 + rt)

Therefore,

r = R/100 = 12%/100 = 0.12 per year.

So:

A = 1200(1 + (0.12 × 5)) = 1920

A = $1,920.00

So, The total amount accrued, principal plus interest, from simple interest on a principal of $1,200.00 at a rate of 12% per year for 5 years is $1,920.00.

At an investment of 1,200 at a 12% interest rate for 9 years:

A = $2,496.00

I = A - P = $1,296.00

Note that

A = P(1 + rt)

Therefore:

r = R/100 = 12%/100 = 0.12 per year.

So:

A = 1200(1 + (0.12 × 9)) = 2496

A = $2,496.00

Therefore, the total amount accrued, principal plus interest, from simple interest on a principal of $1,200.00 at a rate of 12% per year for 9 years is $2,496.00.

At an investment of 1,200 at a 6% interest rate for 9 years.

Note that:

I = A - P = $648.00

The Equation is:

A = P(1 + rt)

Therefore,

r = R/100 = 6%/100 = 0.06 per year.

So

A = 1200(1 + (0.06 × 9)) = 1848

A = $1,848.00

So, The total amount accrued, principal plus interest, from simple interest on a principal of $1,200.00 at a rate of 6% per year for 9 years is $1,848.00.

So, the descriptions of each investment from least to greatest are:

An investment of 1,200 at a 6% interest rate for 9 years- A = $1,848.00.
An investment of 1,200 at a 12% interest rate for 5 years- A = $1,920.00.
An investment of 1,200 at a 12% interest rate for 9 years - A = $2,496.00.

Learn more about simple interest from

brainly.com/question/20690803

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8 0

2 years ago