Answer:
1. E
2. C
3. F
4. D
5. A
6. B
Explanation:
CPU: this is known as the central processing unit and it is considered to be the brain of a computer system. It is the system unit where all of the processing and logical control of a computer system takes place.
A. Decode unit: decodes instructions and data and transmits the data to other areas in an understandable format.
B. Register unit: contains many separate, smaller storage units. Modern CPUs need only a few nanoseconds to execute an instruction when all operands are in its registers.
C. Bus unit: it is used to connect all the other major components together, accepts data, and sends data through the input and output bus sections.
D. Control unit: control of the overall operations of the CPU. The component of the central processing unit (CPU) that controls the overall operation of a computer is the control unit. It comprises of circuitry that makes use of electrical signals to direct the operations of all parts of the computer system. Also, it instructs the input and output device (I/O devices) and the arithmetic logic unit how to respond to informations sent to the processor.
E. Arithmetic logic unit (ALU): performs mathematical functions on data stored in the register area.
F. Cache: small temporary memory area that separates and stores income data and instructions.
Answer:
The CAN-SPAM Act
Explanation:
Email or electronic mail is an information system mechanism of communication, that involves the use of digital devices to initiate communication over the internet. The email uses several protocols like the POP3, IMAP etc.
The CAN-SPAM Act is proposed in the United States law, applicable to email investigations. It requires that a sender provides a mechanism whereby the receiver can opt out of future emails without a fee.
Answer:
Lowest Level; Machine Language.
Explanation:
The lowest level of a computer is machine language, which are strings of 0's and 1's in bits, and it's possible to perform tasks at this level. It's however difficult to do and humans created <em>Assembly</em>; a type of low level programming language to be readable, and converts to machine language so that we don't have to work in binary.
Answer:
names = ['Peter', 'Bruce', 'Steve', 'Tony', 'Natasha', 'Clint', 'Wanda', 'Hope', 'Danny', 'Carol']
numbers = [100, 50, 10, 1, 2, 7, 11, 17, 53, -8, -4, -9, -72, -64, -80]
for index, element in enumerate(names):
if index % 2 == 0:
print(element)
for num in numbers:
if num >= 0:
print(num, end = " ")
count = 0
for i in numbers:
count += i
avg = count/len(numbers)
print("sum = ", count)
print("average = ", avg)
for num in numbers:
if num % 2 != 0:
print(num, end = " ")
Explanation:
I'm stuck on the last two.. I have to do those too for an assignment.
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
