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Mrrafil [7]
3 years ago
11

Antimicrobial susceptibility testing was performed to screen a novel compound. The MIC was found to be 10ng/mL. Use the followin

g data to determine the percent recovery for each treatment group. What is the MBC and would you describe the antimicrobial tested as static or cidal?
Novel compound concentration CFU/mL Present Recovery
0ng mL 3.4 x 10^5
10ng/mL 2.4 x 10^5
20ng/mL 6.4 x 10^4
40ng/mL 1.4 x 10^4
80n mL 4.4 x 10^3
160n mL 0
Biology
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

a) Percent recovery

100%, 70.58%, 4.11%, 1.29% , 0%

b) MBC = 160 ng mL

c) Static

Explanation:

<u>A) Calculate the percent recovery for each group </u>

i) for 0ng mL

( 3.4*10^5 / 3.4*10^5 ) * 100 = 100%

ii) for 10ng mL

( (2.4 * 10^5) / (3.4 * 10^5) ) * 100 = 70.58%

iii) for 20ng mL

( ( 6.4 * 10^5 ) / ( 3.4 * 10^5 ) ) * 100 = Nil

iv) for 40 ng mL

( ( 1.4 * 10^4 ) / ( 3.4 * 10^5 ) ) * 100 = 4.11 %

v) for 80 ng mL

( ( 4.4 * 10^3 ) / ( 3.4 * 10^5 ) ) * 100 = 1.29%

vi) for 160 n mL

percentage recovery = 0%

<u>B) what is the MBC </u>

The value of MBC = 160 n mL because at this concentration CFU/mL = 0

<u>c) determine if the antimicrobial tested is static or cidal </u>

condition : If, the ratio of MBC : MIC  is  ≤4 then novel compound is Cidal

MBC / MIC =  160ng / 10ng = 16 : 1

hence we can conclude that the antimicrobial tested is STATIC

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