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FrozenT [24]
3 years ago
11

Nadine has a cup of nickels and a cup of dimes.

Mathematics
1 answer:
WITCHER [35]3 years ago
3 0

Answer: 135 nickels

Step-by-step explanation:

135 Nickels is $6.75 and 165 dimes is $16.50

That's 300 coins. $6.75 + $16.50 = $23.25

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A clothing salesman want to earn $6000 in March. He receives a base salary of $4000 per mont as well as a 10% commission for all
N76 [4]
He would have to sell $20,000 worth of clothes to get $2,000
6 0
3 years ago
What is the rate of change of the water level , in feet per hour
miskamm [114]
A; rate of change is the same as slope, so, using the slope formula, m= \frac{y_{2} - y\1_{1}   }{ x_{2} - x_{1} }, where m is the slope and x_{1}, x_{2}, y_{1}, and y_{2} are the x and y values.

Plug in 2 points for x and y, water level being the y and time being the x since we're looking for the answer in ft/hr-- you can choose any two, but from the same row.

m= \frac{ 30-50}{4-0}
m= \frac{-20}{4}
m= \frac{-5}{1}
m= -5 ft/hr

4 0
3 years ago
May someone help me out with this please please
torisob [31]
I = PRT/100 I = Simple Interest P = Principal R = Interest Rate per period T = Time ( no. of periods ) Interest = (2500×9.5×3)/100 = 712.50 Answer : $2500 - $712.50 = $1787.50
8 0
3 years ago
Which values are outliers?
SSSSS [86.1K]
Answer:
0.8 Not Outlier
1.1 Not Outlier
10.2 Not Outlier
10.9 Not Outlier 

Solution:
Arranging the numbers in ascending order:
     0.8   1.1   4.9   5.2   5.8   5.9   6.1   6.1   7.4   10.2   10.9
we can see that the median is 5.9.

We can find the first quartile Q1 by getting the median in the lower half of the data 
     0.8   1.1   4.9   5.2   5.8
that is, Q1 = 4.9

We can find the third quartile Q3 by getting the median for the upper half of the data 
     6.1   6.1   7.4   10.2   10.9
that is, Q3 = 7.4

We subtract Q1 from Q3 to find the interquartile range IQR.
     IQR = Q3 - Q1 = 7.4 - 4.9 = 2.5

We can now calculate for the upper and lower limits:
     upper limit = Q3 + 1.5*IQR = 7.4 + (1.5*2.5) = 11.15
     lower limit = Q1 – 1.5*IQR = 0.8 - (1.5*2.5) = -2.95
There is no data point that lies above the upper limit and below the lower limit, therefore, there are no outliers in the data set.
8 0
3 years ago
Read 2 more answers
Complete the following sentence. The coefficient of determination between the dependent variable, TEST SCORE, and the independen
amm1812

Answer: a. variation in the variable, HOURS SPENT STUDYING explains 43% of the variation in the variable. TEST SCORE

Step-by-step explanation:

The coefficient of determination is denoted by R square is the proportion of the variance in the dependent variable that is predictable from the independent variable.

Given:  dependent variable = TEST SCORE

independent variable = HOURS SPENT STUDYING

coefficient of determination = 0.43

That means variation in the variable, HOURS SPENT STUDYING explains 43% of the variation in the variable. TEST SCORE.

Hence, the correct option is a.

8 0
3 years ago
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