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What is the answer for -5(a-6) + 2a

katen-ka-za [31]

Answer:

27a

Step-by-step explanation:

-5(a-6)+2a

-5a+30+2a

-3a+30

27a

7 0

3 years ago

Read 2 more answers

Which of the following is equivalent to f(x)?

Fynjy0 [20]

Answer:

D. $x^{-3/2}$

Step-by-step explanation:

Given function:

$f(x) = \frac{1}{x\sqrt{x} }$

Equivalent expression is:

$\frac{1}{x\sqrt{x} } = x^{-1}x^{-1/2} = x^{-1 - 1/2} = x^{-3/2}$

Correct choice is D

6 0

2 years ago

40 POINTS!! AND BRAINLIEST!! The equation of the line is Y=2.x- 1.8. Based on the graph which of the following are true?

nalin [4]

Answer:

The correct statment is B.

Step-by-step explanation:

A. is not correct: y = 2.4(30) - 1.8 does not equal 70...

B. Is correct because the slope is 2.4 From the equation

C. is not correct because the points have no 2.4 (maybe 2.2)? difference.

D. is not correct. the correlation isn't positive.

7 0

3 years ago

Given that T is the centroid of △DEF and FT=12

dlinn [17]

The centroid of a triangle divides the median of the triangle into 1 : 2

The measure of FQ is 18, while the measure of TQ is 6

Because point T is the centroid, then we have the following ratio

$\mathbf{TQ : FT =1 : 2}$

Where FT = 12.

Substitute 12 for FT in the above ratio

$\mathbf{TQ : 12 =1 : 2}$

Express as fraction

$\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}$

Multiply both sides by 12

$\mathbf{TQ =\frac{1 }{ 2} \times 12}$

This gives

$\mathbf{TQ =\frac{1 2}{ 2}}$

Divide 12 by 2

$\mathbf{TQ =6}$

The measure of FQ is calculated using:

$\mathbf{FQ = FT + TQ}$

Substitute 12 for FT, and 6 for TQ

$\mathbf{FQ = 12 + 6}$

Add 12 and 6

$\mathbf{FQ = 18}$

Hence, the measure of FQ is 18, while the measure of TQ is 6

Read more about centroids at:

brainly.com/question/11891965

6 0

2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago