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julia-pushkina [17]
2 years ago
6

Find the exact solutions to x2 – 3x + 1 = 0 by using the Quadratic Formula.

Mathematics
1 answer:
miss Akunina [59]2 years ago
3 0

Answer:

Step-by-step explanation:

3 +- \/5 over 2

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Is the polynomial prime? <br> 7x2-35x+2x-10
wolverine [178]

The given polynomial is not a prime polynomial.

Given the polynomials, we have to choose the polynomial which is prime.

A polynomial with integer coefficients that cannot be factored into lower degree polynomials is Prime polynomials.

7x^2-35x+2x-10

7x^2-33x-10

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

<h3>What is the formula for the quadratic roots?</h3>

\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=7,\:b=-33,\:c=-10

x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}

x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}

x_{1,\:2}=\frac{-\left(-33\right)\pm \:37}{2\cdot \:7}

x_1=\frac{-\left(-33\right)+37}{2\cdot \:7},\:x_2=\frac{-\left(-33\right)-37}{2\cdot \:7}

x=5,\:x=-\frac{2}{7}

Therefore the factor is (x-5) and (7x+2).

can be factored

∴ not a prime polynomial.

To learn more about the prime polynomial visit:

brainly.com/question/26388060

#SPJ1

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2 years ago
The Cheer Squad is raising money to pay for their trip to the State Finals. They already have $1200 and they are selling really
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Answer:

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We know that they need at least $3000; meaning, it may be $3000 or more. This leaves us with eliminating the bottom two choices.

We then look at the first two choices. If we were to subtract from 1200, we would not know the total income amount that has been gained. It would also eventually give us negative numbers. We cannot have a negative amount earned. Instead, we would use the 10c+1200 because this would allow us to visualize that it needs to be greater than or equal to 3000

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So 2/3 of 120 is 80
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