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Karolina [17]
3 years ago
13

Find x pleaseeeeeeeeee

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0
We could find x by finding the leg of the implied triangle.

We could use Pythagorean’s theorem for this

a^2 + b^2 = c^2

Plug in values

(17)^2 + b^2 = (19)^2

289 + b^2 = 361

b = 6 square root 2

We multiply this by two because there are two of these

This makes it 12 square root 2

Subtract this from 31

This will be 31-12 sqrt 2 or 14.029437...
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If Seth used 4 ounces of black beans, how many beans did he use altogether?​
musickatia [10]

Answer: 4 Ounces.

Step-by-step Explanation: I don't know the full context of the problem, but if Seth used 4 ounces, that means that he used 4 ounces all together.

6 0
2 years ago
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
60% expressed as a ration is StartFraction 60 Over 100 EndFraction. What is this as a fraction in its reduced form?
Fynjy0 [20]

Answer:

3/5

Step-by-step explanation:

60/100 can be reduced down to 6/10 by dividing by 10, and then you can simplify even more by dividing 6/10 by 2, which leaves you with 3/5.

I hope this helps :)

3 0
2 years ago
Read 2 more answers
In ¾ pound of a banana bread, there is ½ cup of cinnamon. How much cinnamon does the bread contain per pound?
Shkiper50 [21]

1 pound of bread contains \frac{2}{3} cups of cinnamon.

<h3><u>Solution:</u></h3>

Given that , In \frac{3}{4} pound of a banana bread, there is \frac{1}{2} cup of cinnamon

<em><u>To find:</u></em>

Amount of cinnamon per pound in bread

Let "n" be the cinnamon per pound present in bread

\frac{3}{4} pound of banana bread ⇒ \frac{1}{2} cup of cinnamon

Then, 1 pound of bread ⇒ n cups of cinnamon

Now, let us use criss cross method (i.e. multiplying the diagonal ordered terms and equating them)

\begin{array}{l}{\rightarrow n \times \frac{3}{4}=\frac{1}{2} \times 1} \\\\ {\rightarrow n \times \frac{3}{4}=\frac{1}{2}} \\\\ {\rightarrow n=\frac{1}{2} \times \frac{4}{3}} \\\\ {\rightarrow n=\frac{2}{3}}\end{array}

Hence, 1 pound of bread contains \frac{2}{3} cups of cinnamon.

3 0
3 years ago
Help plz:)))I’ll mark u Brainliest
noname [10]

Answer:

22-18-25,

19-24-30,

7-24-25

Step-by-step explanation:

In a triangle with side lengths a, b, and c, any two sides must have a sum larger than the third.

Using this rule, the possible side lengths out of these choices that could form a triangle are:

22-18-25,

19-24-30,

7-24-25

7 0
3 years ago
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