We need to satisfy the following equations:
x*y = 13
x + y = -14
Isolating x from the first equation,
x = -14 - y
Substituting this result into the first equation,
(-14 - y)*y = 13
-14y- y*y = 13
-y² - 14y - 13 = 0
Using the quadratic formula,
![\begin{gathered} y_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y_{1,2}=\frac{14\pm\sqrt[]{(-14)^2-4\cdot(-1)\cdot(-13)}}{2\cdot(-1)} \\ y_{1,2}=\frac{14\pm\sqrt[]{144}}{-2} \\ y_1=\frac{14+12}{-2}=-13 \\ y_2=\frac{14-12}{-2}=-1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D%20%5C%5C%20y_%7B1%2C2%7D%3D%5Cfrac%7B14%5Cpm%5Csqrt%5B%5D%7B%28-14%29%5E2-4%5Ccdot%28-1%29%5Ccdot%28-13%29%7D%7D%7B2%5Ccdot%28-1%29%7D%20%5C%5C%20y_%7B1%2C2%7D%3D%5Cfrac%7B14%5Cpm%5Csqrt%5B%5D%7B144%7D%7D%7B-2%7D%20%5C%5C%20y_1%3D%5Cfrac%7B14%2B12%7D%7B-2%7D%3D-13%20%5C%5C%20y_2%3D%5Cfrac%7B14-12%7D%7B-2%7D%3D-1%20%5Cend%7Bgathered%7D)
Therefore, the solution is:
Answer:
ab 112 weeks or ab 778 days
Step-by-step explanation:
2000 / 18 = 111.111111111
If I round up 111.111111111 it would be 112
Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
Answer:
There are 1.25 days in 30 hours or 1 1/4 days in 30 hours
Step-by-step explanation:
As we know one day is 24 hours. So if we divide 30 hours by 24 hours (or one whole day) then we get 1.25 days or also known as 1 1/4 days
