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3 years ago

Which choices correctly describe reflections in the diagram? Check all that apply.

Mathematics

2 answers:

Svet_ta [14]3 years ago

5 0

Answer:

the first one

Step-by-step explanation:

Lunna [17]3 years ago

5 0

Answer:

A.) The red triangle A is reflected across the x-axis onto triangle B.

B.) ✔The red triangle A is reflected across the y-axis onto triangle D.

C.) ✔The blue triangle D is reflected across the x-axis onto triangle C.

D.) ✔The blue triangle D is reflected across the line y = x onto triangle B.

E.) The green triangle C is reflected across the line y = –x onto triangle A.

Step-by-step explanation:

So the answer is B,C, and, D.

Hope this helps

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Please help me with the problem

katrin2010 [14]

Answer:

See the attachment.

Step-by-step explanation:

The approach is to take advantage of the definition of a perpendicular bisector to show the base lengths and right angles are congruent, then use SAS with the second side being CD (congruent to itself). It's mainly a matter of deciding what the various reasons are called.

It seems the goal is to show that AC = BC as marked.

3 0

3 years ago

irakobra [83]

Answer:

a) P(0, 2), Q(4, 0)

b) Please find attached the plot of the points P and Q on a chart made with MS Excel

c) Please find the graph of the line that represent the function 4·x + 2·y = 8 for values of x from -2 to 3 made with the Insert Chart feature on MS Excel

Step-by-step explanation:

The given equation for the line is 4·x + 2·y = 8

a) The coordinates of P = P(0, _)

Therefore, the point 'P', which is the point where the variable y = 0, is the point the (straight line) graph intercepts the x-axis (the x-intercept)

When y = 0 from the given equation, we get;

4·x + 2·y = 8

At the point y = 0;

4·x + 2 × 0 = 8

x = 8/4 = 2

x = 2

∴ The coordinates of P = P(0, _) = P(0, 2)

Similarly, when x = 0, we get;

4·x + 2·y = 8

At the point x = 0;

4 × 0 + 2·y = 8

y = 8/2 = 4

y = 4

∴ The coordinates of Q = Q(_, 0) = Q(4, 0)

b) Rewriting the given equation in terms of 'y' gives;

y = (8 - 4·x)/2 = 4 - 2·x

y = 4 - 2·x

With the help of MS Excel, the points P and Q are plotted in the attached graph

c) The line of the graph of the function 4·x + 2·y = 8 for values of x from -2 to 3 can be added by Changing the Chart Type to 'Scatter with Smooth Lines and Markers' within MS Excel as presented in the included graph of the line.

3 0

3 years ago

Prove whether the quadrilateral is a parallelogram using the Distance & Slope Formulas D(-5, -6), E(5, 2), F(4, -4), G(-6, -

amm1812

Answer:

See the distances bellow

Step-by-step explanation:

Given data

D(-5, -6), E(5, 2)

substitute into the expression for the distance

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((5+5)^2 + (2+6)^2)\\\\d= \sqrt((10)^2 + (8)^2)\\\\d= \sqrt(100 +64)\\\\d= \sqrt((164)\\\\d= 12.80$

E(5, 2), F(4, -4)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((4-5)^2 + (-4-2)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08$

F(4, -4), G(-6, -12)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6-4)^2 + (-12+4)^2)\\\\d= \sqrt((-10)^2 + (-8)^2)\\\\d= \sqrt(100+64)\\\\d= \sqrt((164)\\\\d= 12.80$

G(-6, -12), D(-5, -6)

$d= \sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)\\\\d= \sqrt((-6+5)^2 + (-12+6)^2)\\\\d= \sqrt((-1)^2 + (-6)^2)\\\\d= \sqrt(1+36)\\\\d= \sqrt((37)\\\\d= 6.08$