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3 years ago

What are the dimensions of a 2x4x8

2 answers:

5 0

Answer: Many of you know this, but why is this a thing? You don't go to Subway and pay for a $5-footlong expecting to get 11 inches (although many of you will argue this is the case). And it's not just a 2x4: A 1x4 is actually ¾ inches by 3-½ inches; a 4x4 is actually 3-½ inches by 3-½ inches.

Step-by-step explanation:

Firdavs [7]3 years ago

5 0

If you are asking what they equal up too, your answer is 16

If this isn't, please correct me and I will give you a better answer

You might be interested in

Simplify the expression 6x + 9 + 3x -x by combining like terms?

Arte-miy333 [17]

Answer:

Group the like terms

6x + 3x - x + 9

Work out the x values together and then add the 9

9x - x + 9

8x + 9

your final answer should be about 8x + 9 as it cannot be simplified anymore

7 0

3 years ago

Solve for x.

AfilCa [17]

You need to put the numbers it give you, algo will am I supposed to solve that

3 0

3 years ago

Multiply 2 2/3 and 1 5/6 Simplify the answer and write as a mixed number.

fiasKO [112]

The answer as a mixed number is 4 8/9

The first step is to write out the fractions and multiply both fractions

2 2/3 × 1 5/6

= 8/3 × 11/6

= 44/9

Convert to a mixed number

= 4 8/9 (as a mixed number)

Hence the mixed number gotten from the simplification is 4 8/9

#SPJ1

4 0

1 year ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

I need help with this question.

Papessa [141]

Answer:

It's A, c =2.5d

Step-by-step explanation:

When it comes to problems like this, I usually look through the answers and try to plug in the numbers until I get the right equation that fits with the graph.

2.5(5) = 12.5

2.5(10)= 25

2.5(15)= 37.5

2.5(20) = 50

2.5(25) = 62.5

If you compare this to the graph, you'll notice the solutions are the same as the Total Cost (c). That's because c= 2.5d is the right equation for this graph. (Sorry if my explanation is confusing)

5 0

3 years ago