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Paul [167]
3 years ago
9

Your gas tank holds 13.5 gallons of gas your fuel gauge shows that your tank is one quarter full your car gets an average of 25

miles per gallon the gps show that you are 85 miles from your destination. Your brother says you will make it is he ? Use unit analysis to justify your response
Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

  The brother is likely wrong.

Step-by-step explanation:

The range of the vehicle with a full tank is ...

  (13.5 gal/tank)(25 mi/gal) = 337.5 mi/tank

You have 1/4 tank, so your range is ...

  (337.5 mi/tank)(1/4 tank) = 84.375 mi

If you make the 85 mile distance, it will be because you achieved gas mileage better than average and/or your gas gauge gives you some cushion.

Unit analysis says you do not have the necessary range.

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Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a
EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, \sin x and \cos x are defined for all real numbers.

\tan x=\frac{\sin x}{\cos (x)}, this function is not defined where \cos x=0.

\cot x=\frac{\cos x}{\sin (x)}, this function is not defined where \sin x=0.

\csc x=\frac{1}{\sin (x)}, this function is not defined where \sin x=0.

For option A

The domain of f(x)=\sin(x) is all real numbers.

The domain of g(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

For option B

The domain of f(x)=\cos(x) is all real numbers.

The domain of f(x) =csc(x) is x\ne n\pi

For option C,

The domain of G(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

The domain of f(x) =cot(x) is x\ne n\pi

For option D;

The domain of f(x) =cot(x) is x\ne n\pi

The domain of f(x) =csc(x) is x\ne n\pi

3 0
3 years ago
Read 2 more answers
F(x)= 2x^2 + k/x point of inflection at x=-1 then value of k is
Nady [450]
I think it isss 2 :)))
4 0
3 years ago
If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
seraphim [82]

Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

from (1)(2) => proven

5 0
3 years ago
GCF OF 16 20 and 24 .....
Gemiola [76]

Answer:

the gcf of 16, 20, and 14 is 4

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3 years ago
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Turma:
Roman55 [17]
E porque ya lo use y es facil
3 0
3 years ago
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