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3 years ago

In the figure, what is the measure of <c?

Mathematics

1 answer:

zubka84 [21]3 years ago

7 0

So first 180-70=110
second 360-110-90-90=360-290=70

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A football team had 32 players last year. This year, the team increased by 25%. How many players are on the team this year

qaws [65]

Answer:

40 players

Step-by-step explanation:

Well if it's a 25% increase and 32=100% then 25%=8 players because 32/4=8 then add it to 32 to get 40 players

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3 years ago

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Help me with this asappppppp

adelina 88 [10]

Answer:

875

Step-by-step explanation:

20x5=100

10x30=300

15x30=450

5x5x2=50/2

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3 years ago

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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Please i need asp this is me ether failing or passing math!!!

Citrus2011 [14]

Answer:

Step-by-step explanation:

8 0

3 years ago

Scott likes to run long distances. He can run 20 \text{ km}20 km20, start text, space, k, m, end text in 858585 minutes. He want

aleksandrvk [35]

Answer:

Scott will take 221 minutes to run 52 km

Step-by-step explanation:

Speed

The speed of an object can be calculated with the formula:

$\displaystyle v=\frac{d}{t}$

Where d is the distance traveled and t is the time taken.

Scott can run d=20 km in 85 minutes. Thus, his speed is:

$\displaystyle v=\frac{20}{85}\ km/min$

Now he wants to know how many minutes it will take him to run d=52 km. Solving the formula for t:

$\displaystyle t=\frac{d}{v}$

Since the speed has been already determined:

$\displaystyle t=\frac{52}{\frac{20}{85}}$

Multiplying by the reciprocal of the denominator:

$\displaystyle t=52*\frac{85}{20}$

t = 221 min

Scott will take 221 minutes to run 52 km

4 0

3 years ago

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