What happens to the force between two charged objects when you triple the magnitude of both charges?

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If the force between two charged objects when you triple the magnitude of both charges. The Force will become 9 times the initial force.

<h3>What is coulombs law?</h3>

According to coulombs law force between two charges is given by

$F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}$

Here, R is the distance between both the charges Q and q.

Let the force on the charges be F1

The distance of separation = r

The magnitudes of the charges q1 and q2

K = Coulumb's constant

$F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}$

Let the force on the charges be F

The distance of separation = r

The magnitudes of the charges 3q1 and 3q2

K = Coulumb's constant

So,

$F = \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}$

$F = \dfrac{1}{4\pi \epsilon }\dfrac{3Q\times 3q}{r^2}\\\\F = \dfrac{1}{4\pi \epsilon }\dfrac{9Qq}{r^2}\\\\F =9 \dfrac{1}{4\pi \epsilon }\dfrac{Qq}{r^2}\\\\F = 9F_1$