Question

The coordinates of the vertices of △JKL are J(3, 4), K(3, 1) , and L(1, 1) . The coordinates of the vertices of △J′K′L′ are J′(−3,−5), K′(−3,−2), and L′(−1,−2). Drag and drop the answers into the boxes to correctly complete the statement. A sequence of transformations that maps △JKL to △J′K′L′ is a followed by a

Answer 1

The correct answer is:

A 180° rotation followed by a translation 1 unit down.

Explanation:

The points are mapped as follows:

J(3, 4)→J'(-3, -5)

K(3, 1)→K'(-3, -2)

L(1, 1)→L'(-1, -2)

A 180° rotation maps a point (x, y) to (-x, -y).  This would map

J(3, 4)→(-3, -4)

K(3, 1)→(-3, -1)

L(1, 1)→(-1, -1)

The difference between these points and the image points are that each y-coordinate of the image is 1 lower than these.  This means a translation 1 unit down would result in the image points.

Answer 2

Answer:

Step-by-step explanation:

Given are the coordinates of vertices of △JKL are J(3, 4), K(3, 1) , and L(1, 1) . The coordinates of the vertices of △J′K′L′ are J′(−3,−5), K′(−3,−2), and L′(−1,−2).

On comparison we find that each x  coordinate has changed sign and y coordinate changed sign and 1 unit less.

Hence correct transformation would be

i) A rotation of 180 degrees about the origin.  This makes the coordinates as

(−3,−4), (−3,−1), and (−1,−1)

ii) Now shift 1 unit down vertically  sothat we get the triangle J'K'L'