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MA_775_DIABLO [31]
3 years ago
13

X=2y-6;y=3x-7substitution to solve systems of equations​

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0
<h2>Answer:</h2>

As you said, we can solve this system for y by using <em><u>substitution</u></em>.

x = 2y - 6\\y = 3x - 7\\\\y = 3(2y - 6) - 7\\\\y = 6y - 18 - 7\\\\y = 6y - 25\\\\-5y = -25\\\\y = 5

Now, using what we got for y, we plug it into one of the original equations to solve for x.

x = 2(5) - 6\\\\x = 10 - 6\\\\x = 4

Now we have the solution of this system.

(4, 5)

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Complete the equation of the line through (6,-6) and (8,8).<br> Use exact numbers.<br> y=?
MariettaO [177]
Y = 7x - 48

use slope formula so, y2 - y1 over x2 - x1 to get your m value or your slope which is 7. then plug in the slope and a random set of point so I used (6, -6). -6 = 6(7) + b, simplify.
-6 = 42 + b, subtract 42 which leaves you with b= -48. hope this helps :)
6 0
3 years ago
Two models of cellular telephones, red and blue, are stored in boxes. One box weighs twelve pounds and contains four of the red
GenaCL600 [577]
First, make a equation in which r= red and b=blue.

So, since in the first box it has 4 red models and one blue model equaling 12,

the first equation looks like 4r+b=12.

The second equation looks like 2r+b=8.

What you would do is try and first solve for r by getting rid of b.

Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.

-1*(2r+b=8)= -2r-b=-8

Add.

4r+b=12
+(-2r-b=-8)

2r=4
r=2

Then, you plug in 2 for the r for any of the original equations.

4(2)+b=12

8+b=12

b=4

or

2(2)+b=8

4+b=8
b=4

So, the red models weigh 2 pounds while the blue models weigh 4.



5 0
3 years ago
7. For a school fundraiser, Elena will make T-shirts. She will order T-shirts and print graphics on them. Elena must spend $349
MrRa [10]

Answer: a)

20 shirts | 349 + 20(4.8)

40 shirts | 349 + 40(4.8)

60 shirts | 349 + 60(4.8)

b) Tn = 349 + n(4.8)

c) (1000 - 349)/4.8  rounded down.

7 0
2 years ago
Help me, this is math and I need to this this extension.
Gnom [1K]

Applying pythagorean theorem:-

\\ \sf\longmapsto 8^2-5^2=b^2

\\ \sf\longmapsto 64-25=b^2

\\ \sf\longmapsto b^2=39

\\ \sf\longmapsto b=\sqrt{39}

\\ \sf\longmapsto b=6.24

5 0
3 years ago
Read 2 more answers
If y2 = x3 + 2, which statement is true? The equation is a function at all values of x. The equation is not a function. The equa
tatyana61 [14]

Answer:

The equation is not a function.

Step-by-step explanation:

We are given that

y^2=x^3+2

y=\pm\sqrt{x^3+2}

Function: It is mapping between the values of two sets A and B.

Each element of A has unique value in set B.

By definition of  function

In given function

y has no unique value for each value of x.

Substitute x=0

y=\pm \sqrt{0+2}=\pm \sqrt 2

Hence, it is not a function.

6 0
3 years ago
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