Write the equation of the circle centered at ( – 3, (-3, – 10) with radius 2.
1 answer:
You might be interested in
Answer:
Center of mass at
Step-by-step explanation:
Given a set of objects located at the points
The moments Mx and My are calculated as follows.
and the Center of mass is given at the coordinates where M is the total mass of the system.
We have that m1=3, m2=4 and m3=3, so M = 3+4+3 = 10.
We have that m1 is at point P1(2,-6), m2 at point P2(-3,2) and m3 at point P3 (3,4), then
Then, the center of Mass is at
Answer:
a) (<em>μ</em>) = $128
b) 0.9472
c) 0.6671
Step-by-step explanation:
Given that:
Allegiant Airlines charges a mean base fare of $89.
this implies that: mean base fare = $89.
The question proceeds by stating the additional charge on its website, checking bags, and inflight beverages.
so , additional charges turns out to be = $39 per passenger
Now, Suppose a random sample of 60 passengers is taken
random sample (n) = 60
The population standard deviation of total flight cost is known to be $40
standard deviation (σ) = 40
Question (a) says; we should find the population mean cost per flight
To determine that; we have to consider the total sum(<em>μ</em>) of the mean base fare with the mean additional charges.
Population mean cost per flight (<em>μ</em>) = mean base fare + mean additional charges
(<em>μ</em>) = $89 + $39
(<em>μ</em>) = $128
b)
What is the probability the sample mean will be within $10 of the population mean cost per flight (to 4 decimals)?
To determine that; we have:
P(128 - 10 ≤ Х ≤ 128 +10)
= P(118 ≤ Х ≤ 138)
= (where
= <em>μ </em>and ∝ = σ )
=
=
Using Excel Command to approach this process, we have;
= 0.9736 - 0.0264
= 0.9472 (to four decimal places)
∴ the probability that the sample mean will be within $10 of the population mean cost per flight = 0.9472
c)
What is the probability the sample mean will be within $5 of the population mean cost per flight (to 4 decimals)?
We wll have to go through the process like the one attempted above in question (b);
So;
P(128 - 5 ≤ Х ≤ 128 + 5)
= P(123 ≤ Х ≤ 133)
= (where
= <em>μ </em>and ∝ = σ )
=
=
Computing these data in Excel; we have
= 0.8335 -0.1665
= 0.6671 (to 4 decimal places)
∴ the probability that the sample mean will be within $5 of the population mean cost per flight.