Answer:
0.07215 = 0.072 to 3 d.p.
Step-by-step explanation:
Central limit theorem explains that the sampling distribution obtained from this distribution will be approximately a normal distribution with
Mean = population mean
μₓ = μ = 9.8 minutes
Standard deviation of the distribution of sample means = σₓ = (σ/√n)
σ = 12 minutes
n = sample size = 30
σₓ = (12/√30) = 2.191
Probability that a random sample of 30 overtime periods would have a (sample) mean length of more than 13 minutes
Required probability = P(x > 13)
Since we've established that this distribution of sample means approximates a normal distribution
We first standardize 13 minutes.
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (13 - 9.8)/2.191 = 1.46
Required probability
P(x > 13) = P(z > 1.46)
We'll use data from the normal probability table for these probabilities
P(x > 13) = P(z > 1.46) = 1 - P(z ≤ 1.46)
= 1 - 0.92785 = 0.07215
Hope this Helps!!!
Answer:
41,666.67m2
Step-by-step explanation:
Call W the Width and L the Length with 3 pieces.
The total length will be 2W + 3L
The Area is L*W
so,
A = L*W
2W+3L = 1000
Solve for L
3L = 1000-2W
L = (1000-2W)/3
subtitute for L into the first equation
A = L*W
A = W*(1000-2W)/3
A = (1000W - 2W^2)/3
Now, to find the max, set the 1st derivative = 0. I don't know if you know what that means, but...
dA/dW = 1000/3 - 4W/3 = 0
1000 - 4W = 0
W = 250 meters
Solve for L
2W+3L = 1000
500 + 3L = 1000
3L = 500
L = 166.67 m
Area = 250*500/3 = 41,666.67m2.
Answer:
That's a solid answer there.
Step-by-step explanation:
LOL
Okay, so here is a small lesson on rounding. When you round you MUST know the place value of each number. Ones, tens, hundreds, thousands, millions.
So, when we look at this number what do we have in the ones place --there is a 0 -- in the tens place we have a 9 and in the the thousands place we have 5. to round this number look at the tens place. if the number is greater than 5 you round 73590 to 73600, if it is 4 and lower it stays the same and the numbers behind change to zero--> like so 73500. But for this problem it would round up to 73600.
We'll be looking for time here.
s=d/t
ts=d
t=d/s
------------------------
Average speed is:
s=(55m)/h
Distance is:
200m
---------------------------
t=(200m)/(55m/h)
t=(200m/1)*(h/(55m))
t=200/55*h
t≈3.64 hours
