Step-by-step explanation:
As we know that
- The domain of a relation is defined as the set of all possible independent values the relation can really take - basically the group of all possible inputs.
- The range of a relation is defined as the set of all possible dependent values the relation can generate from the domain values - basically the group of all possible outputs.
For example, considering the set of ordered pairs
As
- The domain is the set of independent values, meaning the set of x-coordinates of the ordered pairs as x is an independent variable.
- The range is set of dependent values, meaning the set of y-coordinates of the ordered pairs as y is an independent variable.
So, in the set of ordered pairs of a relation
Keywords: ordered pairs, domain, range, relation
Learn more about ordered pairs, domain and range from brainly.com/question/5016419
#learnwithBrainly
Answer:
17 minutes i had this same answer and question 2day, so ur lucky.
Step-by-step explanation:
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins
Answer:
Step-by-step explanation:
The attached diagram shows the given triangle labelled as triangle ABC. Line DE is parallel to line AB. It means that triangle DEC is similar to triangle ABC. Comparing the sides,
DC/DE = AC/AB
DC = 5
DE = 8
AC = 5 + x
AB = 10
Therefore,
5/8 = (5+x)/10
Cross multiplying
5 × 10 = 8(5 + x)
50 = 40 + 8x
8x = 50-40 = 10
x = 10/8 = 1.25
Similarly,
CE/DE = CB/AB
CE = 7
CB = 7 + y
DE = 8
AB = 10
Therefore
7/8 = (7+y)/10
Cross multiplying
7 × 10 = 8(7 + y)
70 = 56 + 8y
8y = 70 - 56 = 14
y = 14/8 = 1.75
245in^2
Curved surface = 2pi x r x h = 2 x 3.1 x 3 x 10 = 186
2 ends = 2 x (Pi x r x r) = 2 x 3.1 x 3 x 3 = 55.8
Total area = 186 + 55.8 = 242in^2 approximately
Answer:
23) 36·(3·1/4) = 36·(3/4) = 108/4 = 27
24) (4·2/7)·21 = (8/7)·21 = 168/7 = 24
25) 2(x+4) = 2x+8
26) (5+n)3 = 15+3n
27) (4-3m)8 = 32-24m
28) -3(2x-6) = -6x+18
29) 13r+5r = 18r
30) 3x³-2x²
31) 7m+7-5m = 2m+7
32) 5z²+3z+8z² = 3z+13z²
33) (2-4n)17 = 34-68n
34) 11(4d+6) = 44d+66
35) 7m+2m+5p+4m = 13m+5p
36) 3x+7(3x+4) = 3x+21x+28 = 24x+28
37) 4(fg+3g)+5g = 4fg+12g+5g = 4fg+17g
38) (5m)²+(m+5)²= 26m²+10m+25
39) 7(a²+b)-4(a²+b) = 3(a²+b) = 3a²+b
