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Zanzabum
3 years ago
14

If r(x)=4x^2-3x+7, Find r(2a^2)

Mathematics
1 answer:
Nata [24]3 years ago
7 0

Answer:

r(2a²) = 16a⁴ - 6a² + 7

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

r(x) = 4x² - 3x + 7

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function r(x)]:                                                                            r(2a²) = 4(2a²)² - 3(2a²) + 7
  2. Exponential Rule [Powering]:                                                                           r(2a²) = 4(2²a²⁽²⁾) - 3(2a²) + 7
  3. [Exponents] Multiply:                                                                                        r(2a²) = 4(2²a⁴) - 3(2a²) + 7
  4. Exponents:                                                                                                        r(2a²) = 4(4a⁴) - 3(2a²) + 7
  5. Multiply:                                                                                                             r(2a²) = 16a⁴ - 6a² + 7
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