Okay lets create an eqn from that information
A first int, B second int, C third int, D fourth int.
B = A + 2
C = A + 4
D = A + 6
A is the smallest integer
B + D = 0.5 (A + C)
Now lets substitute
(A + 2) + (A + 6) = 0.5(A + (A + 4))
now lets dist
2a + 8 = 0.5(2a +4)
2a + 8 = a + 2
a + 8 = 2
a = -6
B = -6 +2
B = -4
C = -6 + 4
C = -2
D = -6 + 6
D = 0
Now using B + D = 0.5(A + C)
-4 + 0 = 0.5(-6 + (-2))
-4 = 0.5 (-8)
-4 = -4
Correct
Therefore, First integer is -6, second integer is -4, third integer is -2 and fourth integer is 0
I think the answer is b I havent done problems like that in like 2 years i hope i helped
Well first you times the 0.3 to w and 10 which will give you 0.3w + 3 = 1.8w and subtracting 1.8 from 0.3 gives you
1.5w=3 and that is divided to w=2
Answer:
C. Biased, because she only asked students on honor roll.
Step-by-step explanation:
Since Mrs. Gilbert's goal was to find how many students that spent >4 hours and not how many students that earned Honor Roll that spent >4 hours, the data is biased. Choose C.
3,843,000. the number next to 2 (which is in the thousands place) is 5. so we add one and it became 3,843,000
