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GREYUIT [131]
3 years ago
8

K is between J and L. JK = 3x – 5, and KL = 2x + 1. IfJL = 16, what is JK?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

If JL = 16, we will get JK = 7

Option A is correct option.

Step-by-step explanation:

We are given:

K is between J and L

JK = 3x – 5, and KL = 2x + 1.

IfJL = 16, what is JK

We know that K is between J and L it means it divides JL into JK and KL equally or we can say that adding JK and KL we can get JL

So, We can write:

JL = JK + KL\\16=3x-5+2x+1

Solving the expression we can find first value of x and then value of JK

16=3x-5+2x+1\\16=5x-4\\16+4=5x\\20=5x\\x=\frac{20}{5}\\x=4

So, we get x = 4

Now, put the value of x in JK=3x-5 to get value of JK

JK = 3x-5\\JK=3(4)-5\\JK = 12-5\\JK=7

So, if JL = 16, we will get JK = 7

Option A is correct option.

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Answer:

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C) g(x) has the largest possible y-value

Step-by-step explanation:

f(x)=-5^x+2

f(x) is an exponential function.

Lim x→∞ f(x) = Lim x→∞ (-5^x+2) = -5^(∞)+2 = -∞+2→ Lim x→∞ f(x) = -∞

Lim x→ -∞ f(x) = Lim x→ -∞ (-5^x+2) = -5^(-∞)+2 = -1/5^∞+2 = -1/∞+2 = 0+2→

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g(x)=-5x^2+2

g(x) is a quadratic function. The graph is a parabola

g(x)=ax^2+bx+c

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x=-b/(2a)

b=0

c=2

x=-0/2(-5)

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x=0

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The maximum value of g(x) is 2

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